Question

我想创建一个像这样的python数组：

use galaxy60_1000;

CREATE EXTERNAL TABLE scd_member1 (scd_member_key string) ROW FORMAT DELIMITED FIELDS TERMINATED BY ',' LOCATION '/user/AutomationFiles/galaxy60_1000/scd_member';

CREATE EXTERNAL TABLE scd_member3 (scd_member_key string) ROW FORMAT DELIMITED FIELDS TERMINATED BY ',' LOCATION '/user/AutomationFiles/galaxy60_1000/scd_member';

但是，我想使用一个函数来执行此操作，因此，如果数组的尺寸发生变化，我仍然会得到相同的输出，其中外部元素在数值上增加而中间元素保持为零。

Answer 1

这是尝试使用N和M作为高度和宽度：

N = 5
M = 7

m = []

# first row
m.append([1] + list(range(2*N + 2*M - 4, M + 2*N - 3, -1)))

# middle rows
for i in range(1, N-1):
    row = M*[0]
    row[0] = i+1
    row[-1] = 2*N + M -2 - i
    m.append(row)

# last row
m.append(list(range(N, N+M)))

for row in m:
    strgs = ('{:2d}'.format(n) for n in row)
    print(' '.join(strgs))

它打印：

 1 20 19 18 17 16 15
 2  0  0  0  0  0 14
 3  0  0  0  0  0 13
 4  0  0  0  0  0 12
 5  6  7  8  9 10 11

与numpy中的要求相同

import numpy as np

m =  np.zeros(shape=(N, M), dtype=int)

# first row
m[0] = [1] + list(range(2*N + 2*M - 4, M + 2*N - 3, -1))

# middle rows
for i, row in enumerate(m[1:-1], start=2):
    row[0] = i
    row[-1] = 2*N + M -1 - i

# last row
m[-1] = list(range(N, N + M))

创建一个python数组，其中外部元素按时间顺序增加

1 个答案: