一次调用两个查询时如何避免mysqli错误？

Question

我正在PHP/MySQLi中使用两个mysql查询来将数据更新到mysql数据库。

在此代码中如何使用mysql_use_result()和mysql_free_result()。此php代码中的百老汇正在调用两个更新查询，但现在返回的是空值。有人可以帮助我吗？

这是我的php代码更新记录到数据库。

    $sql_moneyboxs = "SELECT SUM(Amount) AS inflow
    FROM payment_details WHERE DATE(created)='$todayDate' and paymentMode='cash' GROUP BY DATE(created)";       
    //$result2 = mysqli_query($link, $sql_get_sum_cash);
    //$row2    = mysqli_fetch_array($result2);
    //echo json_encode($row2);
    //$sql_get_sum_cash->close();
    //$account = $link->query($sql_moneybox)->fetch_assoc();
    //$row3 = $account->fetch_assoc();





    $sql_moneyboxs .= "SELECT SUM(Amount) AS inflow
    FROM payment_details WHERE DATE(created)='$todayDate' and paymentMode='card' GROUP BY DATE(created)";
    //$result3 = mysqli_query($link, $sql_get_sum_card);
    //$row3    = mysqli_fetch_array($result3);
    //echo json_encode($row3);

    //mysqli_multi_query($link, $sql_moneybox);
    //$profile = $link->query($sql_moneybox)->fetch_assoc();
    //$row2 = $profile->fetch_assoc();


    if (mysqli_multi_query($link, $sql_moneyboxs)) {
 //do {
  if ($result123 = $link->store_result()) {
       while ($row123 = $result123->fetch_row()) {
           //var_dump($row123); //for checking result 
           print($row123);
           //echo $row['inflow'];
          // Now use array to show your result
      }
      $result123->free();

 } if ($link->more_results()) {
     while ($link->next_result()){ 
        $thisresult = $link->store_result();

        print_r($thisresult).'<br />';
    }
   // while (mysqli_next_result($link)) ;
    }
    }
    unset($sql_moneyboxs);