Question

在lodash中是否有一种方法可以找到匹配的名称（假设是唯一的）并在关联位置的数组上进行迭代，即最初返回匹配元素的数组位（filter？pickBy？等）并在其上进行迭代。 / p>

var locations = [ {name:"dave", location:["home","work","pub"]},
                  {name:"alice", location:["school","college","university"]},
                  {name:"fred", location:["us","uk"]} ];

搜索“ fred”，应返回：

0:us
1:uk

我可以使用_.filter和嵌套的_.forEach来做到这一点，但希望对此做得更好：

// _.filter returns the entire element that matches name=who
_.forEach(_.filter( locations, { name:who } ), function(pv,pk){ 
    // returns the array of locations for "who" in 'pv'
    _.forEach(pv.location, function(value,key) { 
        // iterate through the location array one at a time
        console.log ( key+":"+value );
    })
});

Answer 1

尚不清楚您需要什么，因此有两个选择，都不需要lodash：

button.setImage(nil, for: .normal)

Answer 2

// _.filter returns the entire element that matches name=who
_.forEach(_.find( locations, { name:"fred" } ).location, function(value,key){ 
    // iterate through the location array one at a time
    console.log ( key+":"+value );
});

使用Lodash遍历关联数组数据以匹配元素

2 个答案: