Question

我试图从列表中选择一个随机形容词，然后将其显示为标签。

from tkinter import*
import random

root = Tk()
root.geometry("500x500")
root.title("amazing")

    rchoice = ["is smart", " is dumb", " is ugl", " is ugly"]
    random.choice(rchoice)


    def doit():
        text1 = word.get()
        label2 = Label(root, text=text1 +rchoice, font=("Comic Sans MS", 20),  fg="purple").place(x=210, y=350)
        return


    word = StringVar()
    entry1 = Entry(root, textvariable=word, width=30)
    entry1.pack
    entry1.place(x=150, y=90)


    heading = Label(root, text="app of truth", font=("Comic Sans MS", 40), fg="brown").pack()
    Button = Button(root, text="buten", width=15, height=3, font=("Comic Sans MS", 20), fg="blue", bg="lightgreen", command=doit).pack(pady=90)

    root.mainloop()

运行此代码时，它在doit（）函数的{label2“行中返回此错误：TypeError: can only concatenate str (not "list") to str

我了解我需要将列表转换为字符串，该怎么办？

Answer 1

rchoice是一个列表，因此无法将字符串text1与其连接在一起。您应该将random.choice(rchoice)的返回值存储在变量中，然后将text1与该变量连接：

rchoice = ["is smart", " is dumb", " is ugl", " is ugly"]
phrase = random.choice(rchoice)

def doit():
    text1 = word.get()
    label2 = Label(root, text=text1 + phrase, font=("Comic Sans MS", 20),  fg="purple").place(x=210, y=350)
    return

从python中的随机列表中选择时发生错误

1 个答案: