我在特定目录中有一些类(例如src / faa / foo),所有这些类都具有相同的命名空间(App \ faa \ foo)。
我正在寻找一种从php脚本中列出这些类的所有方法的正确方法。
我想做这样的事情:
// list all class of this specific directory
$classes = get_all_class_by_directory_location('src/faa/foo');
// or
$classes = get_all_class_by_namespace('App\foo\faa');
// but that means I must include theses classes to my script isn't it ? I think it's an ugly way because I only need print methods name, I don't need use them in this script
foreach($classes as $class){
print(get_methods($class));
}
什么是我想要做的最好方法?是否存在为此目的维护的社区php软件包?
我的项目遵循psr-4约定,也许此信息有用。
答案 0 :(得分:1)
<?php
foreach (glob('src/faa/foo/*.php') as $file)
{
require_once $file;
// get the file name of the current file without the extension
// which is essentially the class name
$class = basename($file, '.php');
if (class_exists($class))
{
$obj = new $class;
foreach(get_class_methods($obj) as $method)
{
echo $method . '\n';
}
}
}
来自Create instances of all classes in a directory with PHP,然后添加了get_class_methods用法。