Question

我想存储传感器的状态（真/假/未知），我创建了PHP API以返回JSON值而没有任何问题，但是我不能存储空值NULL值（零值swift）在Bool变量中。在这种情况下，是否需要定义var String来存储 ON / OFF / Unknown 值，还是可以使用Bool var来存储true/false/nil？

我用Codable定义Struct

struct nodedata: Codable {
var nodeName: String
var nodeID: String
var temperature: Float
var humidity: Float
var relayStatus: Bool
var lightStatus: Bool
var hallStatus: Bool
var smokeStatus: Bool
var pirStatus: Bool
enum CodingKeys: String, CodingKey {
        case nodeName = "node_name"  //Custom keys
        case nodeID = "node_id"
        case temperature = "temp"
        case humidity = "hum"
        case relayStatus = "relay_status"
        case lightStatus = "light_status"
        case hallStatus = "hall_status"
        case smokeStatus = "smoke_status"
        case pirStatus = "pir_status"
    }
}

下面是存储从JSON获取值的类

class DataManager {
    var nodes = [nodedata]()    // i write main code to store JSON only...
guard let data = data else { return }   // data get from URLSession
                        print(data)
                        let decoder = JSONDecoder()
                        self.nodes = try decoder.decode([nodedata].self, from: data)

我添加了来自服务器的JSON返回

[
  {
    "node_name": "SVIN03",
    "node_id": "y2cfwecrw3hqznuxmfvf",
    "temp": 2132,
    "hum": 111,
    "pir_status": false,
    "smoke_status": false,
    "light_status": false,
    "hall_status": false,
    "relay_status": false
  },
  {
    "node_name": "SVIN04",
    "node_id": "aj2w1aljw8nd65ax79dm",
    "temp": 0,
    "hum": 0,
    "pir_status": false,
    "smoke_status": false,
    "light_status": false,
    "hall_status": false,
    "relay_status": false
  },
  {
    "node_name": "SVIN05",
    "node_id": "mwmfl2og2l8888fjpj2d",
    "temp": 999,
    "hum": 0,
    "pir_status": true,
    "smoke_status": false,
    "light_status": false,
    "hall_status": false,
    "relay_status": false
  }
]

Answer 1

如果传感器具有三种状态，则使用布尔值不是一个好方法，而是可以使用整数标志来告知传感器状态。

使用Bool类型从JSON定义未知值

1 个答案: