Question

我正在尝试使用Ajax从html表单发送输入，并尝试在MySQL数据库中优化电子邮件。我测试了搜索，并且工作正常（使用伪数据。）我的PHP文件在WAMP上运行。我检查了Chrome，以查看是否显示了电子邮件/密码。这是我的代码：

HTML和Ajax

<html>
    <head>
        <!--initialize jquery from js folder-->
        <script src ="js/jquery-3.3.1.min.js"></script>

    </head>
    <body>
            <!--output of the json-->
            <div>
                    <!--set the id to DOM to show output-->
                    <ul id="DOM">

                    </ul>
            </div>
            <form>
                <label><b>Email</b></label>
                <input type="text" placeholder="Enter email" id="email" 
    required>
                <br/>
                <label><b>Password</b></label>
                <input type="text" placeholder="Enter password" id="passwrd" 
    required>
                <br/>
                <button type="button" id="submit">Login</button>
            </form>
            <a href="insert.html">insert</a>
            <a href="delete.html">delete</a>
            <a href="index.html">show data</a>
            <a href="login.html">login</a>

                    <!--Implementation of jquery/ajax-->
        <script type="text/javascript">
            $('#submit').on('click',function(e){
                e.preventDefault()
                var data = {
                    email: $("#email").val(),
                    passwrd: $("#passwrd").val()
                    }
                $.ajax({
                    url : "http://localhost/api/login.php",
                    type : "POST",
                    dataType : "json",
                    data : JSON.stringify(data),
                    //on success it will call this function
                    success : function(data){
                        alert(data.toString());
                        //if fail it will give this error
                    }, error : function(e){
                        alert("failed to work:" +JSON.stringify(e));
                    }
                });
            });
        </script>
        </body>
    </html>

PHP

include "db.php";
    header('Content-type: application/json');
    //$con->escape_string
    $email = isset($_POST['email']);
    //$email = "fk5829@wayne.edu";
    $result = $con->query("SELECT * FROM users WHERE email='$email'");
    echo "$email";
    if($result->num_rows == 0){ //if the user doesnt exist
        $_SESSION['message'] = "user doesnt exist";
        echo ' / user not exist / ';
    }   
    else{ //user exists
        $user = $result->fetch_assoc();
        if(password_verify(isset($_POST['passwrd']), $user['passwrd'])){ 
    //Verify the password entered
            //if password correct, link information from DB to session 
            //variables
            $_SESSION['f_name']= $user['f_name'];
            $_SESSION['l_name']= $user['l_name'];
            $_SESSION['email']= $user['email'];
            $_SESSION['authorized']= $user['authorized'];

            //Will be used to check if users session is logged 
            //in/allowed to do things
            $_SESSION['logged_in'] = true;
            //return to Success
            return $_SESSION['logged_in'];
            exit("Success");
        }
        else{
            $_SESSION['message'] = "You have entered the wrong password, 
    please try again";
        }
        echo ' / user exists / ';
    }
     echo ' / After the check / ';

我的问题是：为什么表单ID为“ email”的电子邮件没有存储在$ email中？在我的ajax请求方面吗？还是我尝试$ _POST时在我的PHP文件中？

任何方向都值得赞赏。

Answer 1

我尝试了此功能并使它起作用。也许您也可以尝试一下。

       <script type="text/javascript">
        $('#submit').on('click',function(e){
            e.preventDefault()
        $.post('http://localhost/api/login.php', {email:$("#email").val(),passwrd:$("#passwrd").val()}, 
            function(data){
                alert(data.toString());
            }).fail(function(e){
                    alert("failed to work:" +JSON.stringify(e));
            });

        });
        </script>

电子邮件未存储在来自ajax请求的变量中

1 个答案: