Question

我们如何将模拟的viewModel注入到Activity中以进行浓缩咖啡测试？使用package ShapesPackage; public class Test { public static void main(String[] args) { Rectangle r = new rectangle(); System.out.println(r.perimeter()); System.out.println(r.semiPerimeter()); RightTriangle t = new rightTriangle(); System.out.println(t.perimeter()); //Fails } }我在Test类中获得了模拟对象，但是Activity收到了常规的viewModel对象。

declareMock

Answer 1

在这种情况下，Espresso测试仍在使用主应用程序类，该类声明了应用程序所需的所有@RunWith(AndroidJUnit4::class) class SomeActivityTest : KoinTest { @Rule @JvmField val rule = ActivityTestRule(SomeActivity::class.java, true, true) val viewModel: MyViewModel by inject() @Before fun setup() { declareMock<MyViewModel>(isFactory = true, binds = listOf(ViewModel::class)) } @After fun cleanUp() { stopKoin() } @Test fun shouldHaveTextViewVisible() { `when`(viewModel.sayHello()) .thenReturn("hello view-model") onView(withId(R.id.tv_homescreen_message)) .check(matches(isDisplayed())) onView(withId(R.id.tv_homescreen_message)) .check(matches(withText("hello view-model"))) } }模块。

在没有任何模块的情况下开始koin可使我们在测试期间仅加载所需的模块。

koin

在开始活动之前声明模拟方法很重要

// application class for espresso tests
class TestApp : Application() {
    override fun onCreate() {
        super.onCreate()
        startKoin(this, emptyList())
    }
}

class TestAppJUnitRunner : AndroidJUnitRunner() {
    override fun newApplication(cl: ClassLoader?, className: String?, context: Context?): Application {
        return super.newApplication(cl, TestApp::class.java.name, context)
    }
}

// app module build.gradle
android {
    defaultConfig {
        testInstrumentationRunner "com.package.TestAppJUnitRunner"
    }
}

Sample code

Koin-如何为咖啡测试提供模拟ViewModel？

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