Question

无论我做什么，我都会得到不正确的结果。谁能给我一些建议：）。

我之前曾发布过问题，但没有得到任何答案，我非常高兴地想要一个答案。

这是我程序的代码，负责获取两个日期之间的时间。

我得到了一个结果，但是问题是它不正确，我很难找到问题。

我必须在项目中访问Joda库。

if (timerightnow.isSelected()) {
            DateFormat getdate = new SimpleDateFormat("dd/MM/yy HH:mm:ss");
            Date getdate1 = new Date(); 

            String datenow = getdate1.toString();

            String monthnow = datenow.substring(4, 7);
            String daynow = datenow.substring(8,10);
            String hournow = datenow.substring(11,19);
            String yearnow = datenow.substring(25, 29);

            if (monthnow.equalsIgnoreCase("jan"))
                monthnow = "01";
            if (monthnow.equalsIgnoreCase("feb"))
                monthnow = "02";
            if (monthnow.equalsIgnoreCase("mar"))
                monthnow = "03";
            if (monthnow.equalsIgnoreCase("apr"))
                monthnow = "04";
            if (monthnow.equalsIgnoreCase("may"))
                monthnow = "05";
            if (monthnow.equalsIgnoreCase("jun"))
                monthnow = "06";
            if (monthnow.equalsIgnoreCase("jul"))
                monthnow = "07";
            if (monthnow.equalsIgnoreCase("agu"))
                monthnow = "08";
            if (monthnow.equalsIgnoreCase("sep"))
                monthnow = "09";
            if (monthnow.equalsIgnoreCase("oct"))
                monthnow = "10";
            if (monthnow.equalsIgnoreCase("nov"))
                monthnow = "11";
            if (monthnow.equalsIgnoreCase("dec"))
                monthnow = "12";

            String timenow = monthnow + "/" + daynow + "/" + yearnow + " " + hournow;
            String timetotext = timeto.getText();
            SimpleDateFormat date = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");


            Date datestart = null;
            Date dateend = null;



             try {

                 datestart = date.parse(timenow);
                 dateend = date.parse(timetotext);

                 DateTime datestartdaytime = new DateTime(datestart);
                 DateTime dateenddaytime = new DateTime(dateend);

                 JOptionPane.showMessageDialog(null, datestartdaytime + "\n" + dateenddaytime);

                int monthoutput = Months.monthsBetween(datestartdaytime, dateenddaytime).getMonths();
                int daysoutput = Days.daysBetween(datestartdaytime, datestartdaytime).getDays() % 30;
                int hoursoutput = Hours.hoursBetween(datestartdaytime, datestartdaytime).getHours() % 24;
                int minutsoutput = Minutes.minutesBetween(datestartdaytime, dateenddaytime).getMinutes() % 60;
                int secondsoutput = Seconds.secondsBetween(datestartdaytime, dateenddaytime).getSeconds() % 60;

                answer.setText(monthoutput + "Months" + daysoutput + "Days" + hoursoutput + "Hours" + minutsoutput + "Minutes" + secondsoutput + "Seconds");

非常感谢：）

Answer 1

我不太了解您要实现的目标。但是您绝对不能自己执行解析逻辑，因为它已经存在于JodaTime中。

这应该可以解决解析问题：

DateTimeFormatter formatter = DateTimeFormat.forPattern("dd/MM/yy HH:mm:ss");
DateTime dt = formatter.parseDateTime(string);

如果您无法解决此问题，请提供更多详细信息。

希望有帮助！

你好乔达时间没有给我正确的结果

1 个答案: