我有这个查询,向我显示了1小时的间隔。我的问题是,将其设置为1小时时,它可以显示从12AM到11PM的完美数据。
SELECT
FROM_UNIXTIME(UNIX_TIMESTAMP(t_stamp) - MOD(UNIX_TIMESTAMP(t_stamp), 3600)) as Tstamp,
Col1,
Col2
FROM table
WHERE DATE(t_stamp) BETWEEN '2018-10-15' AND '2018-10-15'
GROUP BY Tstamp
ORDER BY t_stamp ASC
此输出看起来像这样
Tstamp Col1 Col2
2018-10-15 00:00:00 73.43 72.12
2018-10-15 01:00:00 73.29 71.96
2018-10-15 02:00:00 73.43 72.21
.
.
.
.
.
2018-10-15 16:00:00 74.24 72.85
2018-10-15 17:00:00 74.37 72.85
2018-10-15 18:00:00 74.20 72.64
2018-10-15 19:00:00 74.01 72.42
2018-10-15 20:00:00 73.80 72.42
2018-10-15 21:00:00 73.73 72.34
2018-10-15 22:00:00 73.59 72.13
2018-10-15 23:00:00 73.51 72.12
但是当我将间隔设置为3小时或8小时时,它不是从午夜开始,例如,如果所选日期是2018-10-15,并且间隔设置为3小时,则它是从2018-10开始-14 11:00 PM而不是2018-10-15 12:00 AM
SELECT
FROM_UNIXTIME(UNIX_TIMESTAMP(t_stamp) - MOD(UNIX_TIMESTAMP(t_stamp), 10800)) as Tstamp,
Col1,
Col2
FROM table
WHERE DATE(t_stamp) BETWEEN '2018-10-15' AND '2018-10-15'
GROUP BY Tstamp
ORDER BY t_stamp ASC
这是间隔为3小时时的输出
Tstamp Col1 Col2
2018-10-14 23:00:00 73.43 72.12
2018-10-15 02:00:00 73.43 72.21
2018-10-15 05:00:00 73.73 72.42
2018-10-15 08:00:00 73.29 71.96
2018-10-15 11:00:00 73.36 72.34
2018-10-15 14:00:00 73.98 72.64
2018-10-15 17:00:00 74.37 72.85
2018-10-15 20:00:00 73.80 72.42
2018-10-15 23:00:00 73.51 72.12
我希望在间隔为3小时8小时的情况下获得这样的输出,如果选择的日期为2018-10-15,它将开始于午夜12点而不是前一天的时间。
Tstamp Col1 Col2
2018-10-15 00:00:00 73.43 72.21
2018-10-15 03:00:00 73.72 72.99
2018-10-15 06:00:00 73.34 72.12
2018-10-15 09:00:00 73.43 72.77
2018-10-15 12:00:00 73.29 72.42
2018-10-15 15:00:00 74.15 72.76
2018-10-15 18:00:00 74.20 72.64
2018-10-15 21:00:00 73.73 72.34
.
.
.
非常感谢您的帮助。谢谢
结构和样本数据
CREATE TABLE `table` (
`Col1` float DEFAULT NULL,
`Col2` float DEFAULT NULL,
`t_stamp` datetime DEFAULT NULL,
KEY `tablet_stampndx` (`t_stamp`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `table`
(`Col1`,
`Col2`,
`t_stamp`)
VALUES
('73.43','72.12','2018-10-15 00:00:00'),
('73.29','71.96','2018-10-15 01:00:00'),
('73.43','72.21','2018-10-15 02:00:00'),
('73.72','72.99','2018-10-15 03:00:00'),
('73.80','72.55','2018-10-15 04:00:00'),
('73.73','72.42','2018-10-15 05:00:00'),
('73.34','72.12','2018-10-15 06:00:00'),
('73.94','73.20','2018-10-15 07:00:00'),
('73.29','71.96','2018-10-15 08:00:00'),
('73.43','72.77','2018-10-15 09:00:00'),
('73.43','72.12','2018-10-15 10:00:00'),
('73.36','72.34','2018-10-15 11:00:00'),
('73.29','72.42','2018-10-15 12:00:00'),
('73.51','72.34','2018-10-15 13:00:00'),
('73.98','72.64','2018-10-15 14:00:00'),
('74.15','72.76','2018-10-15 15:00:00'),
('74.24','72.85','2018-10-15 16:00:00'),
('74.37','72.85','2018-10-15 17:00:00'),
('74.20','72.64','2018-10-15 18:00:00'),
('74.01','72.42','2018-10-15 19:00:00'),
('73.80','72.42','2018-10-15 20:00:00'),
('73.73','72.34','2018-10-15 21:00:00'),
('73.59','72.13','2018-10-15 22:00:00'),
('73.51','72.12','2018-10-15 23:00:00')
到目前为止,我已经尝试使用DATE_SUB函数,但它并没有真正提供所需的输出。我在日期间隔上选择了10-15
,但是它向我显示了10-14
的数据,这确实不是我想要查看的内容
SELECT
t_stamp,
Col1,
Col2
FROM table
WHERE t_stamp BETWEEN DATE_SUB('2018-10-15 00:00:00', INTERVAL 3 HOUR)
AND DATE_ADD('2018-10-15 23:59:59', INTERVAL 3 HOUR)
GROUP BY t_stamp
ORDER BY t_stamp ASC
2018-10-14 21:02:17 73.50 72.21
2018-10-14 21:07:17 73.51 72.21
2018-10-14 21:12:17 73.50 72.21
2018-10-14 21:17:17 73.50 72.19
2018-10-14 21:22:17 73.50 72.21
2018-10-14 21:27:17 73.50 72.21
答案 0 :(得分:1)
这是你的追求吗?
SELECT DISTINCT SEC_TO_TIME((FLOOR(TIME_TO_SEC(t_stamp)/10800)*10800))x FROM `table`;