Question

我有一个文件名为fopen，另一个文件名为showRelayTeams.php

我正在尝试将具有数据库功能的那个放到一个名为databaseSELECTOperation.php

的那个里。

showRelayTeam.php

showRelayTeams.php

databaseSELECTOperation.php

<?php
$House = $_GET['q'];

$Data = "No Data";

$Query = "SELECT Firstname, Lastname, AgeGroup, Event, Value FROM tblEventEntries WHERE House = '" . $House . "' ORDER BY Value ASC;";

require("http://127.0.0.1/phpscripts/databaseOperations.php");

$Data = databaseSELECTOperation($Query);

$Counter = 0;

if (mysqli_num_rows($Data) > 0) {
    echo "<table>";
    echo "<tr>";
    echo "<th>Name</th>";
    echo "<th>Age Group</th>";
    echo "<th>Event</th>";
    echo "<th>Time</th>";
    echo "<th>Select?</th>";
    echo "</tr>";

    while ($Row = mysqli_fetch_assoc($Data)) {
        $Counter++;
        echo "<tr>";
        echo "<td>" . $Row["Firstname"] . " " . $Row["Lastname"] . "</td>";
        echo "<td>" . $Row["AgeGroup"] . "</td>";
        echo "<td>" . $Row["Event"] . "</td>";
        echo "<td>" . $Row["Value"] . "</td>";
         echo "<td><input type='checkbox' id='" . $Counter . "'  
onclick='boxChecked(this.id)'></td>";
        echo "</tr>";
     }
}

echo "</table>";
?>

我收到以下错误：

致命错误：未捕获错误：调用未定义函数databaseSELECTOperation（）

当我在require语句之后插入以下代码时，我得到了

找不到功能

<?php
//use the SQL SELECT command and return the data
function databaseSELECTOperation($Query) {
    //this file will include the host, username, password and the database name
    include "http://127.0.0.1/includes/variables.php";

    //start a connection to the database using the credentials
    $Connection = mysqli_connect($DatabaseHost, $Username, $Password, $DatabaseName);

    //if the connection to the database was not successfully made then
    if (!$Connection) {
        //end the script and then print an error
        die("Could not connect to the database: " . mysqli_error());
    } //end if

    //run the query and put the data returned in to a variable
    $DataReturned = mysqli_query($Connection, $Query);

    //return the data to the script that called it
    return $DataReturned;
}
?>

关于如何解决此问题的任何想法？

Answer 1

那是错误：

require("http://127.0.0.1/phpscripts/databaseOperations.php");

当您通过URL引用文件时，它包括Web服务器已经处理的输出，而您需要包括源PHP代码。

相反，您需要像以下示例一样在文件系统上指定文件的路径：

require('../phpscripts/databaseOperations.php');
require('/var/www/html/phpscripts/databaseOperations.php');
require('C:\inetpub\html\phpscripts\databaseOperations.php');

服务器运行时，为什么PHP文件没有包含在文件中？

1 个答案: