Question

我有一个程序，用户必须从线性搜索数组中选择所需的元素。当用户输入1继续时，我的程序应再次显示问题和给定的数组。我不确定while循环必须在哪里以及while循环中应该包含什么代码，因为如果用户输入1继续我的程序，则它不会继续，它只会结束这是我的代码：

import java.util.Scanner;

public class SearchArray 
{

public  static int Search(int[] data, int key)
{

 for (int i = 0; i < data.length; i++)
   {
        if (data[i] == key)
            {
                return i;
            }//end of if statement
   }//end of for loop
        return -1;
 }//end of search method 
public static void main(String[] args) 
{
    Scanner in = new Scanner(System.in);

    int [] data= {74,56,45,14,78,100};
    for(int element: data)
    {
        System.out.print(element + " , "); 
    }

    System.out.println("Enter the key of your choice: ");
    int key = in.nextInt();
    int index = Search(data, key);
    int option = 1;
    System.out.println("Enter 1 to continue: ");
    while(option ==1)
    {

        option=in.nextInt();
    }
    if(index!=-1)
        {
            System.out.println("Key: " + key + " Found at index: " + Search(data, key));
        }//end of if statement
        else
        {
            System.out.println("Key: " + key + " Is not found ");
        }//end of else statement

}//end of main method 
}//end of main class

Answer 1

创建自己的新类。即

if(sc.nextInt() == 1){
   SearchArray sa = new SearchArray();
   sa.main();
}

Answer 2

尝试使用这种主要方法

public static void main(String... args) {

    Scanner in = new Scanner(System.in);

    int[] data = {74, 56, 45, 14, 78, 100};
    for (int element : data) {
        System.out.print(element + " , ");
    }


    while (true) {
        System.out.println("Enter the key of your choice: ");
        int key = in.nextInt();
        int index = Search(data, key);
        System.out.println("Key: " + key + " Found at index: " + index);
        System.out.println("Enter 1 to continue: ");
        while (in.nextInt() != 1) {
            System.out.println("Enter 1 to continue: ");
        }
    }
}

要求用户按1继续后，如何使程序再次运行？

2 个答案: