Question

数据不是静态的，由+分隔的字符组可能会有所不同。我希望所有用+分隔的字符按行排列，然后在其顶部应用聚合。我在Windows中使用mysql 5.7.14。假设数据是：

group   val
a+b     10
a       5
b       6
b+d+c   12
d       13
c+d     12

输出应为：

grp_item val
a        15
b        28
c        24
d        24

Answer 1

就像我说的那样，MySQL查询很复杂。
通常的想法是一个MySQL数字生成器，它生成1到10000，因此它支持10000个在group列中带有+符号的分隔值。
而且+号之间的数据无关紧要。

查询

SELECT 
   Table1_unique_groups.`group`
 , SUM(Table1.val)
FROM (

SELECT 
 DISTINCT
   SUBSTRING_INDEX(SUBSTRING_INDEX(Table1.`group`, '+', number_generator.number), '+', -1) AS `group`

FROM (
  SELECT 
   @row := @row + 1 AS number
  FROM (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) record_1
  CROSS JOIN (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) record_2    
  CROSS JOIN (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) record_4
  CROSS JOIN (
    SELECT 0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3 UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 UNION SELECT 8 UNION SELECT 9
  ) record_5     
  CROSS JOIN (
    SELECT @row := 0 
  ) AS init_user_params
) AS number_generator
CROSS JOIN 
 Table1 

) AS Table1_unique_groups

INNER JOIN 
  Table1
ON
  FIND_IN_SET(Table1_unique_groups.`group`, REPLACE(Table1.group, '+', ','))

GROUP BY 
 Table1_unique_groups.`group`

结果

| group | SUM(Table1.val) |
| ----- | --------------- |
| a     | 15              |
| b     | 28              |
| c     | 24              |
| d     | 37              |

DB Fiddle demo

使用'+'分隔符将字符串拆分为单独的行并应用聚合

1 个答案: