Question

我有这样的查询：

mysql> SELECT
    -> ir.id, ir.no_surat, link.condition_id
    -> FROM inspection_report ir
    ->
    -> LEFT JOIN link_item_condition_ir_to_ir link
    -> ON link.inspection_id = ir.id
    ->
    -> WHERE ir.no_surat LIKE '%E67%'
    -> ORDER BY ir.no_surat ASC, link.condition_id DESC;

+------+---------------+--------------+
| id   | no_surat      | condition_id |
+------+---------------+--------------+
| 7561 | E6779/10/2018 |            1 |
| 7562 | E6780/10/2018 |            5 |
| 7562 | E6780/10/2018 |            1 |
| 7563 | E6781/10/2018 |            5 |
| 7563 | E6781/10/2018 |            1 |
+------+---------------+--------------+
5 rows in set (0.03 sec)

请在no_surat栏中查看。

有3个唯一的no_surat。我的目标是：选择没有condition_id = 5的数据。

我也已经尝试过，

mysql> SELECT
-> ir.id, ir.no_surat, link.condition_id
-> FROM inspection_report ir
->
-> LEFT JOIN link_item_condition_ir_to_ir link
-> ON link.inspection_id = ir.id
->
-> WHERE ir.no_surat LIKE '%E67%'
-> AND
-> condition_id != 5
->
-> ORDER BY ir.no_surat ASC, link.condition_id DESC;
+------+---------------+--------------+
| id   | no_surat      | condition_id |
+------+---------------+--------------+
| 7561 | E6779/10/2018 |            1 |
| 7562 | E6780/10/2018 |            1 |
| 7563 | E6781/10/2018 |            1 |
+------+---------------+--------------+
3 rows in set (0.02 sec)

但仍然无法正常工作，请告知。

我期望的结果是，忽略所有具有condition_id = 5的'no_surat'列

+------+---------------+--------------+
| id   | no_surat      | condition_id |
+------+---------------+--------------+
| 7561 | E6779/10/2018 |            1 |
+------+---------------+--------------+

谢谢

该查询如何：

mysql> SELECT
    -> ir.id, ir.no_surat, link.condition_id
    -> FROM inspection_report ir
    ->
    -> LEFT JOIN link_item_condition_ir_to_ir link
    -> ON link.inspection_id = ir.id
    ->
    -> WHERE ir.no_surat LIKE '%E67%'
    -> GROUP BY ir.id
    ->
    -> HAVING GROUP_CONCAT( link.condition_id ) NOT LIKE "%5%";
+------+---------------+--------------+
| id   | no_surat      | condition_id |
+------+---------------+--------------+
| 7561 | E6779/10/2018 |            1 |
+------+---------------+--------------+
1 row in set (0.00 sec)

看起来不错吗？

这是小提琴：sqlfiddle

Answer 1

使用此条件：

NOT EXISTS(SELECT 1 FROM link_item_condition_ir_to_ir
           WHERE inspection_id  = ir.id AND condition_id = 5)

代替condition_id != 5。

Answer 2

SELECT ir.id, ir.no_surat, link.condition_id 
FROM inspection_report ir 
LEFT JOIN link_item_condition_ir_to_ir link
ON link.inspection_id = ir.id
WHERE ir.no_surat LIKE '%E67%' AND
ir.no_surat NOT IN 
 (SELECT ir.no_surat 
  FROM inspection_report ir 
  LEFT JOIN link_item_condition_ir_to_ir link
  ON link.inspection_id = ir.id 
  WHERE condition_id = 5)
ORDER BY ir.no_surat ASC, link.condition_id DESC;

Answer 3

请尝试在“查询”下面，我正在使用您的查询来获取结果。

npm install

如果您想更好地查询，请共享您的数据库结构（Schema）：）

Answer 4

使用“不存在”

SELECT t.* from     
    (select ir.id, ir.no_surat, link.condition_id
     FROM inspection_report ir   
    LEFT JOIN link_item_condition_ir_to_ir link
    ON link.inspection_id = ir.id
     ) t where 
             NOT EXISTS ( select 1 from link_item_condition_ir_to_ir
                           t1 where t1.inspection_id=t.id and t1.condition_id=5
                         )

http://www.sqlfiddle.com/#!9/647c0e/3

id      no_surat            condition_id
7561    E6779/10/2018         1

MySql-从具有特定元素的选择查询中忽略数据

4 个答案: