如何在golang中将数据插入多维数组?

时间:2018-10-16 08:54:28

标签: php arrays go multidimensional-array

我有一个动态的多维数组,我需要从循环中动态填充。我该如何定义数组并填充数据。

这是我正在尝试的代码

var arrDetails[][]string
var index int = 0
for _, orderdetails := range ordersfromdb {
    arrDetails[index]["OrderNumber"] = "001"
    arrDetails[index]["customernum"] = "cust_001"
    arrDetails[index]["orderstatus"] = "open"
    arrDetails[index]["orderprice"] = "200"
    index++
}

我面临的错误:

non-integer slice index "OrderNumber"
non-integer slice index "customernum"
non-integer slice index "orderstatus"
non-integer slice index "orderprice"

我已经在php中完成了同样的工作,并且效果完美:

for ($i=0;$i<5:$i++)
{
     $arr_orderdetails[$i]["OrderNumber"] = "001";
     $arr_orderdetails[$i]["customernum"] = "cust_001";
     $arr_orderdetails[$i]["orderstatus"] = "open";
     $arr_orderdetails[$i]["orderprice"] = "200";
}

我是golang的新手,无法找到哪里出了问题,非常感谢您的帮助。

谢谢:)

4 个答案:

答案 0 :(得分:2)

让我们考虑以下解决方案:

arrDetails := map[int]map[string]string{}

index := 0
for _, orderdetails := range ordersfromdb {
    arrDetails[index] = map[string]string{} // you have to initialize map

    arrDetails[index]["OrderNumber"] = "001"
    arrDetails[index]["customernum"] = "cust_001"
    arrDetails[index]["orderstatus"] = "open"
    arrDetails[index]["orderprice"] = "200"

    index++
}

要将结果转换为json(如我所见,您在对@liao yu的答案的评论中提出疑问),我们应该了解有关tags的更多信息:

import (
    "encoding/json"
    "fmt"
)

type OrderDetails struct {
    Number   string `json:"number"`
    Customer string `json:"customer"`
    Status   string `json:"status"`
    Price    string `json:"price"`
}

func main() {
    ordersfromdb := []int{1, 2, 3}

    var arrDetails []OrderDetails
    for _, v := range ordersfromdb {
        arrDetails = append(arrDetails, OrderDetails{
            Number:   fmt.Sprintf("order_number_%v", v),
            Customer: fmt.Sprintf("customer_%v", v),
            Status:   fmt.Sprintf("order_status_%v", v),
            Price:    fmt.Sprintf("$%v", v),
        })
    }

    data, err := json.Marshal(arrDetails)
    if err != nil {
        panic(err)
    }
    fmt.Println(string(data))
}

在操场上观看:https://play.golang.org/p/IA0G53YX_dZ

答案 1 :(得分:0)

正如您在此处将arrDetails变量定义为[][]string的多维切片一样,这意味着您无法将string分配到其keys中,而可以将字符串分配为值。

您可以像下面提到的那样编写代码。

package main

import (
    "fmt"
)

func main() {
  var arrDetails [][]string
  var s []string
  var index int
  for i:=0; i<5;i++ {
     s = []string{"001", "cust_001", "open", "200"}
     arrDetails = append(arrDetails, s)
     index++
  } 
fmt.Printf("Hello, playground %+v", arrDetails )
}

或者,如果您想要keysvalue配对,则必须将map用作:

var arrDetails map[string]string

答案 2 :(得分:0)

根据评论中的volker建议,我将如下填充多维数组

arrDetails[index][0] = "001"
arrDetails[index][1] = "cust_001"
arrDetails[index][2] = "open"
arrDetails[index][3] = "200"

答案 3 :(得分:0)

您可以尝试以下操作:

import "fmt"

func main() {

    var arrDetails []map[string]string
    var index int = 0

    //for _, orderdetails := range ordersfromdb {
    for i:=0; i<5;i++ {
        detail := make(map[string]string)

        detail["OrderNumber"] = "001"
        detail["customernum"] = "cust_001"
        detail["orderstatus"] = "open"
        detail["orderprice"] = "200"
        arrDetails = append(arrDetails, detail)

        index++
    }
    fmt.Printf("Hello, playground %+v", arrDetails )
}