Question

我需要从重叠的日期列表中获取不相互重叠的日期范围的列表，并获取重叠期间的硬币总和。我尝试使用谷歌搜索作为示例，但到目前为止还没有运气。我可能没有使用正确的关键词吗？

我有一个重叠的日期列表

1.1.2018 - 31.1.2018 80
7.1.2018 - 10.1.2018 10
7.1.2018 - 31.1.2018 10
11.1.2018 - 31.1.2018 5
25.1.2018 - 27.1.2018 5
2.2.2018 - 23.2.2018 100

希望的结果是

1.1.2018 - 6.7.2018 80 coins
7.1.2018 - 10.1.2018 100 coins
11.1.2018 - 24.1.2018 95 coins
25.1.2018 - 27.1.2018 100 coins
28.1.2018 - 31.1.2018 95 coins
2.2.2018 - 23.2.2018 100 coins

这里是一个数字，它应该如何工作

|------------------------------|
       |---|
       |-----------------------|
           |-------------------|
                      |---|
                                   |----------------------|
Outcome              
|------|---|----------|---|----|   |----------------------|
   80   100     95     100  95                100

这是我的测试数据

drop table coinsonperiod2;
create table coinsonperiod2(
  id serial,
  startdate date,
  enddate date,
  coins integer,
  userid integer
);
insert into coinsonperiod2 (startdate, enddate, coins,userid) values
  ('2018-01-01','2018-01-31', 80,1)
, ('2018-01-07','2018-01-10', 10,1)
, ('2018-01-07','2018-01-31', 10,1)
, ('2018-01-11','2018-01-31', 5,1)
, ('2018-01-25','2018-01-27', 5,1)
, ('2018-02-02','2018-02-23', 100,2)
, ('2018-01-01','2018-01-31', 80,2)
, ('2018-01-07','2018-01-10', 10,2)
, ('2018-01-07','2018-01-31', 10,2)
, ('2018-01-11','2018-01-31', 5,2)
, ('2018-01-25','2018-01-27', 5,2)
, ('2018-02-02','2018-02-23', 100,3)
;

更新：实际上，StephenM和Joop的答案无法达到我想要的结果。这两个答案都显示enddate错误。

当一个周期结束时，下一个周期应从第二天开始（如果有间隔，则应稍后）。在我期望的结果中，1.1.2018-6.1.2018包括第六天。第六和第七之间没有差距，因为7.1.2018-10.1.2018中包含第七。

UPDATE2：现在，我了解了打开，半打开和关闭间隔之间的区别。在跳跃解决方案中，必须针对半开间隔进行计算，但我希望的结果是闭间隔。这就是为什么必须减少终止日期以使结果成为封闭间隔的原因。如果我错了请纠正我。

我还在示例数据中添加了用户ID，并修改了Joops解决方案。这是给我我想要的结果的查询。

with changes AS (
  SELECT
    userid,
    startdate AS tickdate,
    coins,
    1         AS cover
  FROM coinsonperiod2
  UNION ALL
  -- add 1 day to correct intervals into half open intervals, so the calculation is correct
  SELECT
    userid,
    1 + enddate AS tickdate,
    -1 * coins,
    -1          AS cover
  FROM coinsonperiod2
)
, sumchanges  AS (
    SELECT
      userid,
      tickdate,
      SUM(coins) AS change,
      SUM(cover) AS cover
    FROM changes
    GROUP BY tickdate, userid
)
, aggregated AS (
    SELECT
      userid   AS userid,
      tickdate AS startdate,
      lead(tickdate)
      over www AS enddate,
      sum(change)
      OVER www AS cash,
      sum(cover)
      OVER www AS cover
    FROM sumchanges
    WINDOW www AS (
      partition by userid
      ORDER BY tickdate )
)
-- reduce 1 day from the enddate to make closed interval
SELECT
userid
, startdate
, enddate-1 as enddate
, cash
, cover
FROM aggregated
WHERE cover > 0
ORDER BY userid, startdate
;

结果：

Answer 1

好像我发现了一个丑陋的作品

select t1.dt, t1.enddt, sum(coins)
from (
    select distinct cp1.dt, min(cp2.dt) enddt
    from ( select startdate as dt from coinsonperiod union all select enddate as dt from coinsonperiod ) cp1, 
         ( select startdate as dt from coinsonperiod union all select enddate as dt from coinsonperiod ) cp2
    where cp2.dt > cp1.dt
    group by cp1.dt
    order by cp1.dt ) t1, coinsonperiod t2
where t1.dt between t2.startdate and t2.enddate
and t1.enddt between t2.startdate and t2.enddate
group by t1.dt, t1.enddt

输出：

dt         |enddt      |sum |
-----------|-----------|----|
2018-01-01 |2018-01-07 |80  |
2018-01-07 |2018-01-10 |100 |
2018-01-10 |2018-01-11 |90  |
2018-01-11 |2018-01-25 |95  |
2018-01-25 |2018-01-27 |100 |
2018-01-27 |2018-01-31 |95  |
2018-02-02 |2018-02-23 |100 |

与您的输出唯一的不同是，我想您忘记了01/10和01/11之间的时间间隔

Answer 2

逻辑是：

在间隔的开始处将其值添加到累积总和
在间隔的末端减去该值的值
但是要清除日期线，我们必须收集（唯一的）日期/时间戳记，开始或结束。

因此，重点是：将数据从一系列时间间隔转换为一系列（开始/停止）事件，并对其进行汇总。

-- \i tmp.sql

create table coinsonperiod(
  id serial,
  startdate date,
  enddate date,
  coins integer
);
insert into coinsonperiod (startdate, enddate, coins) values
  ('2018-01-01','2018-01-31', 80)
, ('2018-01-07','2018-01-10', 10)
, ('2018-01-07','2018-01-31', 10)
, ('2018-01-11','2018-01-31', 5)
, ('2018-01-25','2018-01-27', 5)
, ('2018-02-02','2018-02-23', 100)
        ;

WITH changes AS (
    SELECT startdate AS tickdate , coins
            , 1 AS cover
    FROM coinsonperiod
    UNION ALL
    -- add 1 day to convert to half-open intervals
    SELECT 1+enddate AS tickdate, -1* coins
            , -1 AS cover
    FROM coinsonperiod
    )
, sumchanges  AS (
        SELECT tickdate, SUM(coins) AS change, SUM(cover) AS cover
        FROM changes
        GROUP BY tickdate
        )
, aggregated AS (
        SELECT
        tickdate AS startdate
        , lead(tickdate) over www AS enddate
        , sum(change) OVER www AS cash
          -- number of covered intervals
        , sum(cover) OVER www AS cover
        FROM sumchanges
        WINDOW www AS (ORDER BY tickdate)
        )
             -- substract one day from enddate to correct back to closed intervals
SELECT startdate, enddate-1 AS enddate, cash, cover
FROM aggregated
WHERE cover > 0
ORDER BY startdate
        ;

Answer 3

好的，即时消息将为您提供逻辑位和可以在网上找到的语法。

您可以做的是创建一个临时表并将数据移动到那里，然后选择数据的每一行，并为每个列数据将值存储在声明的变量中。

然后只需使用游标，然后从源表中选择所有数据，然后再次使用大于或小于运算符的法线并按自己的方式获取计数。

简单获取第1行第1列，并与所有其他第1列和第2列数据进行比较。

Answer 4

正确答案：

这是我的测试数据

drop table coinsonperiod2;
create table coinsonperiod2(
  id serial,
  startdate date,
  enddate date,
  coins integer,
  userid integer
);
insert into coinsonperiod2 (startdate, enddate, coins,userid) values
  ('2018-01-01','2018-01-31', 80,1)
, ('2018-01-07','2018-01-10', 10,1)
, ('2018-01-07','2018-01-31', 10,1)
, ('2018-01-11','2018-01-31', 5,1)
, ('2018-01-25','2018-01-27', 5,1)
, ('2018-02-02','2018-02-23', 100,2)
, ('2018-01-01','2018-01-31', 80,2)
, ('2018-01-07','2018-01-10', 10,2)
, ('2018-01-07','2018-01-31', 10,2)
, ('2018-01-11','2018-01-31', 5,2)
, ('2018-01-25','2018-01-27', 5,2)
, ('2018-02-02','2018-02-23', 100,3)
;

UPDATE2：现在，我了解了打开，半打开和关闭间隔之间的区别。在跳跃解决方案中，必须针对半开间隔进行计算，但我希望的结果是闭间隔。这就是为什么必须减少终止日期以使结果成为封闭间隔的原因。如果我错了请纠正我。

我还在示例数据中添加了用户ID，并修改了Joops解决方案。这是给我我想要的结果的查询。

with changes AS (
  SELECT
    userid,
    startdate AS tickdate,
    coins,
    1         AS cover
  FROM coinsonperiod2
  UNION ALL
  -- add 1 day to correct intervals into half open intervals, so the calculation is correct
  SELECT
    userid,
    1 + enddate AS tickdate,
    -1 * coins,
    -1          AS cover
  FROM coinsonperiod2
)
, sumchanges  AS (
    SELECT
      userid,
      tickdate,
      SUM(coins) AS change,
      SUM(cover) AS cover
    FROM changes
    GROUP BY tickdate, userid
)
, aggregated AS (
    SELECT
      userid   AS userid,
      tickdate AS startdate,
      lead(tickdate)
      over www AS enddate,
      sum(change)
      OVER www AS cash,
      sum(cover)
      OVER www AS cover
    FROM sumchanges
    WINDOW www AS (
      partition by userid
      ORDER BY tickdate )
)
-- reduce 1 day from the enddate to make closed interval
SELECT
userid
, startdate
, enddate-1 as enddate
, cash
, cover
FROM aggregated
WHERE cover > 0
ORDER BY userid, startdate
;

结果：

从重叠的日期范围中获取不同的连续日期范围

4 个答案: