Question

我有一堆视频剪辑，我想为每个剪辑选择一组音乐。
我编写了一个脚本，该脚本会遍历每个剪辑，并根据其长度随机选择mp3。
例如。如果片段持续10:30，则它会累加几个mp3，长度总和等于片段的长度。

#!/bin/bash
for v in clips/*; do
videolength=$(ffprobe -v error -show_entries format=duration -of default=noprint_wrappers=1:nokey=1 $v | awk '{print int($0)}');
mp3s=0
names=""
    for m in music/*; do
    audiolength=$(ffprobe -v error -show_entries format=duration -of default=noprint_wrappers=1:nokey=1 $m | awk '{print int($0)}');
        while [[ $videolength -ge $mp3s ]]; do
            (( mp3s+=audiolength ))
            names+=$v" "
            mv "$m" "used/$m"
            break
        done
    continue
    done
echo "music for this clip: "${names[*]}
# ffmpeg things here
done

此脚本可以正常工作，只是它会从我的100多个mp3列表中迭代相同的第一个mp3。
如何标记为已使用并跳过已使用的mp3 ，然后在下一个剪辑中仅选择新鲜的mp3？

当前该脚本将mp3移至另一个文件夹，但这似乎并不明智。
有什么聪明的方法可以仅在嵌套循环内遍历新文件吗？

Answer 1

尝试一下：

#!/bin/bash
used=""
for v in clips/*; do
    videolength=$(ffprobe -v error -show_entries format=duration -of default=noprint_wrappers=1:nokey=1 "$v" | awk '{print int($0)}');
    mp3s=0
    names=""
    for m in music/*; do

        # check if the file "$m" was already used
        # "$used" is a newline separated file with names in it
        # we filter out "$m" from it. If it exists, that means that it was used.
        if <<<"$used" grep -q -x "$m"; then
           echo "File $m was already used"
           continue;
        fi

        audiolength=$(ffprobe -v error -show_entries format=duration -of default=noprint_wrappers=1:nokey=1 "$m" | awk '{print int($0)}');
        if (( videolength >= mp3s )); then # I guess you meant if not while, cause it has break on the end, so it acts as if
            (( mp3s += audiolength ))
            names+=$v" " # didn't you mean "$m" here?

            # save "$m" to the list of used files.
            used+="$m"$'\n'

        fi
    done
    echo "music for this clip: "${names[*]}

     # ffmpeg things here

done

您可以将使用的名称保存在以换行符分隔的变量内。然后在列表上使用grep来检查名称是否已被使用。

Bash Shell在新文件上继续嵌套循环

1 个答案: