Question

数组在代码中给出，我的输入是两个数字，例如2, 7，并且在数组的第二个和第七个元素之间，代码需要查找所有偶数之和。我该怎么做？

#include <iostream>
using namespace std;

int main(){
    int S, n1, n2;
    cont int n = 8;
    int found = 0;

    cout << "Enter the beginning of a range: ";
    cin >> n1;

    cout << "Enter the end of a range: ";
    cin >> n2;

    int a[] = {1, 5, 9, 6, 2, 7, 4, 3};

    int i;
    for(i = 0;i <= n; i++){
        if(a[i] % 2 == 0){
        S = S + a[i];
        found = 1;
        }
    }
    if(found == 1){
        cout << "Even numbers found" << " " << "Sum: " << S <<endl;
    }
    else{
        cout << "Even numbers not found" <<endl;
    }
    return 0;
}

Answer 1

由于要对开始和结束之间的数字求和，因此需要更改循环以使用输入的值。更改为此：

gcloud beta firestore export gs://myapp-backup-dev --collection-ids='testStuff'

gcloud beta firestore import gs://myapp-backup-dev/2018-10-15T21:38:18_36964 --collection-ids='testStuff'

此外，删除根本不需要的行for(int i = n1; i <= n2; i++){ if(a[i] % 2 == 0){ S = S + a[i]; found = 1; } }。

Answer 2

尝试一下：

#include <iostream>
using namespace std;
int main()
{
    int S, n1, n2;
    cont int n = 8; 
    int found = 0;
    cout << "Enter the beginning of a range: ";
    cin >> n1;
    cout << "Enter the end of a range: ";
    cin >> n2;
    int a[] = { 1, 5, 9, 6, 2, 7, 4, 3 };
    int i;
    for (; n1 <= n2; n1++)
    {
        if (a[n1] % 2 == 0)
        {
            S = S + a[n1];
            found = 1;
        }
    }
    if (found == 1)
    {
        cout << "Even numbers found" << " " << "Sum: " << S << endl;
    }
    else
    {
        cout << "Even numbers not found" << endl;
    }
    return 0;
}

我有一个数组，我想输入一个range，然后找到该范围内所有偶数的和？

2 个答案: