Question

因此，我正在创建一个函数来计算员工的工资，并输出工资以及他们工作的加班时间。

输出看起来像这样：

Enter hours worked (-1 to end): 41
Enter hourly rate of the worker ($00.00): 10.00
Employee worked 1 hour(s) overtime for a value of $15.00
Salary is $415.00

我唯一的问题是函数在上面的输出之后结束。如何不断询问用户输入-1之前的工作时间？这就是我所拥有的：

#include <iostream>

int main()
{
    double salary;
    int hours;
    int overtime;
    double rate;
    int work_limit = 40;
    double overtimePay;

    std::cout << "Enter hours worked (-1 to end): ";
    std::cin >> hours;

    if(hours < 0);
    std::cout << "Enter hourly rate of worker ($00.00): ";
    std::cin >> rate;

    overtime = hours - work_limit;
    overtimePay = (overtime * rate) + (0.5 * rate * overtime);

    if(hours > work_limit)
        std::cout << "Employee worked " << overtime << " hour(s overtime for a value of $" << overtimePay << std::endl;

    salary = hours * rate;

    salary = (work_limit *  rate) + (overtime * rate * 1.5);
    std::cout << "Salary is: $" << salary << "\n\n";
}

Answer 1

您可以简单地将核心部分包装在while循环中：

// loop infinitely
// exit from loop happens via if check right below
while(true){
    std::cout << "Enter hours worked (-1 to end): ";
    std::cin >> hours;

    // check wether the user wants to end
    // and if so, break out of the loop
    if (hours == -1) {
        break;
    }

    std::cout << "Enter hourly rate of worker ($00.00): ";
    std::cin >> rate;

    overtime = hours - work_limit;
    overtimePay = (overtime * rate) + (0.5 * rate * overtime);

    if(hours > work_limit)
        std::cout << "Employee worked " << overtime << " hour(s overtime for a value of $" << overtimePay << std::endl;

    salary = hours * rate;

    salary = (work_limit *  rate) + (overtime * rate * 1.5);
    std::cout << "Salary is: $" << salary << "\n\n";
}

计算员工工资的C ++函数

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