我在这里有一个代码:
print('Hello Alex! Please tell me how many different shells you collected.')
pukaAlex = int(input('Puka: '))
coneAlex = int(input('Cone: '))
driftwoodAlex = int(input('Driftwood: '))
seaglassAlex = int(input('Sea Glass: '))
starfishAlex = int(input('Starfish: '))
lstAlex = [pukaAlex, coneAlex, driftwoodAlex, seaglassAlex, starfishAlex]
print('Hello Bay! Please tell me how many different shells you collected.')
pukaBay = int(input('Puka: '))
coneBay = int(input('Cone: '))
driftwoodBay = int(input('Driftwood: '))
seaglassBay = int(input('Sea Glass: '))
starfishBay = int(input('Starfish: '))
lstBay = [pukaBay, coneBay, driftwoodBay, seaglassBay, starfishBay]
lstAlexTwo = [('Puka', pukaAlex), ('Cone', coneAlex),
('Driftwood', driftwoodAlex), ('Sea Glass', seaglassAlex),
('Starfish', starfishAlex)]
lstBayTwo = [('Puka', pukaBay), ('Cones', coneBay),
('Driftwood', driftwoodBay), ('Sea Glass', seaglassBay),
('Starfish', starfishBay)]
print('Alex\'s List: ', lstAlexTwo)
print('Bay\'s List: ', lstBayTwo)
我知道我还有其他组合列表选项,但是我不确定如何将Alex和Bay列表中的Pukas和Cones数量与 for
循环组合在一起创建两者的总和,同时创建一个新列表。
我知道我可以使用+字符将两者相加
示例输出:
[('Puka', 52), ('Cone', 21)]
假设收集到的Puka总数为52,而Cones为21。
答案 0 :(得分:0)
这是您可以组合值的方式。然后,您可以做最后的操作,并用新列表中的字符串敲打它们。
newList = []
for i in range(len(lstBay)):
newList.append(lstBay[i] + lstAlex[i])
答案 1 :(得分:0)
尝试一下:
new_list = [(name, val1+val2) for (name, val1), (_, val2) in zip(lstAlexTwo, lstBayTwo)]