Kotlin异步与启动

时间:2018-10-15 15:55:01

标签: kotlin kotlinx.coroutines

Kotlin_version ='1.2.41'

我对Kotlin很陌生。我想知道asynclaunch有什么区别。特别是在以下代码中

import kotlinx.coroutines.experimental.async
import kotlinx.coroutines.experimental.awaitAll
import kotlinx.coroutines.experimental.delay
import kotlinx.coroutines.experimental.launch
import kotlinx.coroutines.experimental.runBlocking

fun main(args: Array<String>) {
    runBlocking {
        (20..30).forEach {
            launch{
                println("main before" + it)
                val outer = it
                delay(1000L)
                val lists = (1..10)
                        .map { async{anotherMethod(outer, it)}}
                println("main after------------------Awaiting" + it)
                lists.awaitAll()
                println("Done awaiting -main after-----------------" + it)

            }


        }

        println("Hello,") // main thread continues here immediately
    }
}

suspend fun anotherMethod (outer: Int,index: Int){
    println("inner-b4----" + outer + "--" + index)
    delay(3000L)
    println("inner-After----" + outer + "--" + index)
}

Vs

fun main(args: Array<String>) {
    runBlocking {
        (20..30).forEach {
            async{
                println("main before" + it)
                val outer = it
                delay(1000L)
                val lists = (1..10)
                        .map { async{anotherMethod(outer, it)}}
                println("main after------------------Awaiting" + it)
                lists.awaitAll()
                println("Done awaiting -main after-----------------" + it)

            }


        }

        println("Hello,") // main thread continues here immediately
    }
}

suspend fun anotherMethod (outer: Int,index: Int){
    println("inner-b4----" + outer + "--" + index)
    delay(3000L)
    println("inner-After----" + outer + "--" + index)
}

1 个答案:

答案 0 :(得分:5)

async确实返回了Deferred<>,而launch只返回了Job,两者都启动了一个新的协程。因此,这取决于您是否需要返回值。

在您的第一个示例中,launch不返回值-最后一个println仅产生一个Unit。如果在第二个示例中使用async,则总体结果将相同,但是创建了一些无用的Deferred<Unit>对象。