Question

我正在制作一个每472毫秒显示一次随机数的应用程序，每次按屏幕五次，然后清除屏幕，直到再次按屏幕。现在，我只是在进行时间安排和所有工作，直到之后才需要清除屏幕。我在代码中收到错误。 “无法解析方法'generateRandomNumber（）'”。我该如何解决？

我的XML：

<LinearLayout
android:id="@+id/linearLayout"
android:layout_width="0dp"
android:layout_height="0dp"
android:clickable="true"
android:onClick="perform_action"
android:orientation="vertical"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintHorizontal_bias="0.0"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent">

<RelativeLayout
    android:layout_width="match_parent"
    android:layout_height="match_parent">

    <TextView
        android:id="@+id/textView1"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_centerInParent="true"
        android:layout_gravity="center_horizontal|center_vertical"
        android:layout_marginBottom="75dp"
        android:gravity="center"
        android:textSize="400sp"
        app:layout_constraintEnd_toEndOf="parent"
        app:layout_constraintHorizontal_bias="0.5"
        app:layout_constraintStart_toStartOf="parent" />

    </RelativeLayout>
</LinearLayout>
</android.support.constraint.ConstraintLayout>

还有我的Java：

public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
}

public int perform_action(View view) {
    final List< Integer > randomNumbers = new ArrayList<>();
    Observable.intervalRange(0, 5, 0, 472, TimeUnit.MILLISECONDS)
            .map(aLong -> {
                int previous = randomNumbers.size() > 0 ? randomNumbers.get(
                        randomNumbers.size() - 1) : -1;
                int randomNumber = generateRandomNumber();
     while (randomNumber == previous) randomNumber = generateRandomNumber();
                randomNumbers.add(randomNumber);
                return randomNumber;
            })
            .observeOn(AndroidSchedulers.mainThread())
            .subscribe(integer -> {
                    TextView tv = (TextView) findViewById(R.id.textView1);
                    tv.setText(String.valueOf(integer));
                });

private int generateRandomNumber() {
    Random r = new Random();
    int minNumber = 1;
    int maxNumber = 9;
    return r.nextInt( ( maxNumber - minNumber ) + 1 ) + minNumber;
    }
}
}

Answer 1

由于perform_action被定义为int，因此它也需要返回一个integer。但是，这似乎没有必要。这应该适合您的目的。由于您只是将TextView设置为string-int，所以我做了一些更改：

public class MainActivity extends AppCompatActivity {

    private TextView tv;
    @Override
    protected void onCreate(@Nullable Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        tv = (TextView) findViewById(R.id.textView1);
        perform_action();

    }

    public void perform_action() {
        final List<Integer> randomNumbers = new ArrayList<>();
        Observable.intervalRange(0, 5, 0, 472, TimeUnit.MILLISECONDS)
                .map(aLong -> {
                    int previous = randomNumbers.size() > 0 ? randomNumbers.get(
                            randomNumbers.size() - 1) : -1;
                    int randomNumber = generateRandomNumber();
                    while (randomNumber == previous) randomNumber = generateRandomNumber();
                    randomNumbers.add(randomNumber);
                    return randomNumber;
                })
                .observeOn(AndroidSchedulers.mainThread())
                .subscribe(integer -> {
                    tv.setText(String.valueOf(integer));
                });

    }

    private int generateRandomNumber() {
        Random r = new Random();
        int minNumber = 1;
        int maxNumber = 9;
        return r.nextInt((maxNumber - minNumber) + 1) + minNumber;
    }

}

您可以根据需要进行更改。

如何解决“无法解析方法'generateRandomNumber（）'”？

1 个答案: