我有POST请求api调用,以从客户端(邮递员或Java客户端)接受json主体请求参数和多部分文件。
我想在单个请求中同时传递json数据和多部分文件。
我已经写了如下代码。
@RequestMapping(value = "/sendData", method = RequestMethod.POST, consumes = "multipart/form-data")
public ResponseEntity<MailResponse> sendMail(@RequestPart MailRequestWrapper request) throws IOException
但是,我无法使用邮递员休息客户端来完成它。
我在服务器端使用Spring Boot。
有人可以在这个问题上建议我吗。
预先感谢
答案 0 :(得分:4)
您可以将@RequestParam和Converter用于JSON对象
简单的例子:
@SpringBootApplication
public class ExampleApplication {
public static void main(String[] args) {
SpringApplication.run(ExampleApplication.class, args);
}
@Data
public static class User {
private String name;
private String lastName;
}
@Component
public static class StringToUserConverter implements Converter<String, User> {
@Autowired
private ObjectMapper objectMapper;
@Override
@SneakyThrows
public User convert(String source) {
return objectMapper.readValue(source, User.class);
}
}
@RestController
public static class MyController {
@PostMapping("/upload")
public String upload(@RequestParam("file") MultipartFile file,
@RequestParam("user") User user) {
return user + "\n" + file.getOriginalFilename() + "\n" + file.getSize();
}
}
}
更新
apache httpclient 4.5.6
示例:
pom.xml依赖项:
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.5.6</version>
</dependency>
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpmime</artifactId>
<version>4.5.6</version>
</dependency>
<!--dependency for IO utils-->
<dependency>
<groupId>commons-io</groupId>
<artifactId>commons-io</artifactId>
<version>2.6</version>
</dependency>
服务将在应用程序完全启动后运行,请更改文件的File
路径
@Service
public class ApacheHttpClientExample implements ApplicationRunner {
private final ObjectMapper mapper;
public ApacheHttpClientExample(ObjectMapper mapper) {
this.mapper = mapper;
}
@Override
public void run(ApplicationArguments args) {
try (CloseableHttpClient client = HttpClientBuilder.create().build()) {
File file = new File("yourFilePath/src/main/resources/foo.json");
HttpPost httpPost = new HttpPost("http://localhost:8080/upload");
ExampleApplication.User user = new ExampleApplication.User();
user.setName("foo");
user.setLastName("bar");
StringBody userBody = new StringBody(mapper.writeValueAsString(user), MULTIPART_FORM_DATA);
FileBody fileBody = new FileBody(file, DEFAULT_BINARY);
MultipartEntityBuilder entityBuilder = MultipartEntityBuilder.create();
entityBuilder.addPart("user", userBody);
entityBuilder.addPart("file", fileBody);
HttpEntity entity = entityBuilder.build();
httpPost.setEntity(entity);
HttpResponse response = client.execute(httpPost);
HttpEntity responseEntity = response.getEntity();
// print response
System.out.println(IOUtils.toString(responseEntity.getContent(), UTF_8));
} catch (Exception e) {
e.printStackTrace();
}
}
}
控制台输出如下所示:
ExampleApplication.User(name=foo, lastName=bar)
foo.json
41
答案 1 :(得分:1)
我在回答部分解释了一切:
答案 2 :(得分:0)
您有两个选择-
与JSON数据一起发送MultipartFile
public void uploadFile(@RequestParam("identifier") String identifier, @RequestParam("file") MultipartFile file){
}
OR
在MultipartFile中发送Json数据,然后按以下所述解析Multipart文件,就这样。
public void uploadFile(@RequestParam("file") MultipartFile file){POJO p = new ObjectMapper().readValue(file.getBytes(), POJO.class);
}
答案 3 :(得分:0)
过去几个小时,我一直被这个问题困扰
所以我遇到了this个问题。
摘要:
使用@ModelAttribute
代替@RequestBody
。
@ModelAttriute
的工作原理与其他普通(实体中没有multipart属性的)实体映射一样。