如果子菜单中的任何一个处于活动状态,则需要在父导航项中的.nav-link中添加一个活动类。
<ul>
<li class="nav-item">
<a class="nav-link" (click)="BEDropdownOpen = !BEDropdownOpen" [attr.aria-expanded]="BEDropdownOpen"
aria-controls="basic-elements-dropdown">
Elements
</a>
<div class="collapse" id="basic-elements-dropdown" [ngbCollapse]="!BEDropdownOpen">
<ul class="nav flex-column sub-menu">
<li class="nav-item">
<a class="nav-link" routerLink="/accordions" routerLinkActive="active">Accordion</a>
</li>
<li class="nav-item">
<a class="nav-link" routerLink="/typography" routerLinkActive="active">Typography</a>
</li>
<li class="nav-item">
<a class="nav-link" routerLink="/tooltips" routerLinkActive="active">Tooltip</a>
</li>
</ul>
</div>
</li>
</ul>
如果div.collapse中的任何.nav-link具有活动类, 一个活动的类应该添加到父nav-item内的nav-link
答案 0 :(得分:1)
您可以为每个链接创建一个模板变量,然后使用ngClass
来分配类,如下所示:
<ul>
<li class="nav-item">
<a
class="nav-link"
(click)="BEDropdownOpen = !BEDropdownOpen"
[attr.aria-expanded]="BEDropdownOpen"
[ngClass]="{'active': accordionLink.isActive || typographyLink.isActive || tooltipLink.isActive}"
aria-controls="basic-elements-dropdown">Elements
</a>
<div class="collapse" id="basic-elements-dropdown" [ngbCollapse]="!BEDropdownOpen">
<ul class="nav flex-column sub-menu">
<li class="nav-item">
<a class="nav-link" routerLink="/accordions" routerLinkActive="active" #accordionLink="routerLinkActive">Accordion</a>
</li>
<li class="nav-item">
<a class="nav-link" routerLink="/typography" routerLinkActive="active" #typographyLink="routerLinkActive">Typography</a>
</li>
<li class="nav-item">
<a class="nav-link" routerLink="/tooltips" routerLinkActive="active" #tooltipLink="routerLinkActive">Tooltip</a>
</li>
</ul>
</div>
</li>
</ul>
答案 1 :(得分:1)
您可以使用program main
use gfunc_module
implicit none
integer, parameter :: dp = kind(1.0d0)
real(dp) :: x = 1.
integer, parameter :: n = 4
integer, parameter :: m = 4
real(dp), dimension(n) :: a = [-1., -0.33333333, .033333333, 1.]
real(dp), dimension(m) :: b = [-1., -0.33333333, .033333333, 1.]
real(dp), dimension(n, m) :: c
call gfunc(x, n, m, a, b, c)
write(*,*) c
end program main
的{{1}}属性,然后在父元素上使用isActive
。
routerActiveLink
答案 2 :(得分:0)
使用@ T.Shashwat的想法。您声明ViewChildren和一个吸气剂
@ViewChildren('rla') links:QueryList<routerLinkActive>
get isActive(){
return this.links?this.links.find(x=>x.isActive)!=null:false
}