Question

我有一个接收参数并返回json作为响应的服务。响应json如下所示

{
    "status": 0,
    "message": "You are successfully registered",
    "user": [
        {
            "name": "Rajiv",
            "dob": "10/12/1988",
            "gender": 1,
            "qualification": "1",
            "streams": "1",
            "contactno": "3423234333",
            "email": "rajiv88@gmail.com",
            "password": "testpass",
            "api_key": "29b9522d1bd23161db5aba89933a6015",
            "profilepic": "NA",
            "phverified": 0,
            "emverified": 0,
            "active": 0
        }
    ]
}

我已经编写了如下界面：

@FormUrlEncoded
@POST("v20/register")
Call<RegisterResponse> insertUser(
        @Field("name_of_user") String name,
        @Field("dob") String dob,
        @Field("gender") int gender,
        @Field("qualification") String qualification,
        @Field("streams") String streams,
        @Field("contactno") String contactno,
        @Field("email") String email,
        @Field("password") String password);

注册响应类别如下

import java.util.List;
import com.google.gson.annotations.Expose;
import com.google.gson.annotations.SerializedName;
import com.sbs.data.User;

public class RegisterResponse {

    @SerializedName("status")
    @Expose
    private Integer status;
    @SerializedName("message")
    @Expose
    private String message;
    @SerializedName("user")
    @Expose
    private List<User> user = null;

    public Integer getStatus() {
        return status;
    }

    public void setStatus(Integer status) {
        this.status = status;
    }

    public String getMessage() {
        return message;
    }

    public void setMessage(String message) {
        this.message = message;
    }

    public List<User> getUser() {
        return user;
    }

    public void setUser(List<User> user) {
        this.user = user;
    }

}

我按如下方式调用服务函数：

Call<RegisterResponse> call=jobApiService.insertUser(edName.getText().toString(),
                edDob.getText().toString(),
                spnGender.getSelectedItemPosition()+1,
                categoryIDString, subCategoryIDString, txtPhone.getText().toString(), edmail.getText().toString(),
                edpass.getText().toString());
        call.enqueue(new Callback<RegisterResponse>() {
            @Override
            public void onResponse(Call<RegisterResponse> call, Response<RegisterResponse> response) {

                Log.d("hj", "Number of users received: " + response.body().getMessage());

            }
            @Override
            public void onFailure(Call<RegisterResponse> call, Throwable throwable) {
                Log.d("hj", "Error");

            }
        });

但是我收到

NullPointerException

此陈述时

Log.d（“ hj”，“接收的用户数：” + response.body（）。getMessage（））;

执行。

有人可以提出解决方案吗

Answer 1

检查是否从远程服务器得到响应。如果为null，则使用邮差或其他任何工具分别测试您的api。如果可行，请检查您的请求代码。

public void onResponse(Call<RegisterResponse> call, Response<RegisterResponse> response) {

    if(resonse.body != null && !TextUtils.isEmpty(response.body().getMessage())){
        Log.d("hj", "Number of users received: " + response.body().getMessage());
    } else {
        Log.d("hj", "response received is null, but why??");
    }

}

Answer 2

尝试为列表用户删除初始化器null。

Answer 3

我们已经以这种方式发送数据

身体类型-> 原始对于这种类型，我们已经在模型中发送数据

@POST("user")
fun userInsert(@Body userModel: UserRequestModel): Observable<Response>

{
  "email": "abcd@abcd.com",
  "password": "123123"
}

身体类型-> x-www-form-urlencoded 这样的

@POST("user")
 fun userInsert(@Body userHm:  HashMap<String,String>): Observable<Response>

 Hasmap <String, String> hm =new Hasmap<>()
 hm.put("Key", value)

身体类型-> 表单数据 多部分需要此类型

使用RetroFit2执行发布请求时发生NullPointerException

3 个答案: