Question

我有日期：

  var addresses = context.Addresses;
  var contracts = context.Contracts;

  foreach(var a in contracts) {
      new MyDto() {
        AddressId = addresses.Where(x => a.AddressId == x.AddressId).Select(y => y.AddressNumber);
        AddressName = addresses.Where(x => a.AddressId == x.AddressId).Select(y => y.FullName);
        Date= a.Date,
        AnotherDate = a.AnotherDate,
        Text = a.Text,
        VerweisAdrId = addresses.Where(x => a.VerweisAdrId == x.AddressId).Select(y => y.AddressNumber);
        VerweisAdrName = addresses.Where(x => a.VerweisAdrId == x.AddressId).Select(y => y.FullName);
      }
  }

我想在日期列中减去dateTo=pd.to_datetime('today').strftime('%Y-%m-%d')：

dateTo

所需的输出将是带有减法输出的新列number dates coord AC 10 2018-07-10 11.54 AC 10 2018-07-11 11.19 AN 5 2018-07-12 69.40。我希望此输出为整数。

我尝试的是在Pandas: Subtracting two date columns and the result being an integer处给出的答复：

df['datepond']

在numpy 1.12.1版本中，它工作得很好，但即时通讯现在是numpy 1.15.2，并且输出

df['datepond']=(pd.Timestamp(dateTo)-pd.to_datetime(df['dates']))/ np.timedelta64(1, 'D')

如何获得所需的输出？

Answer 1

您可以尝试Timestamp.floor删除时间，并将时间增量转换为天Series.dt.days：

df['datepond']= (pd.to_datetime('today').floor('d') - pd.to_datetime(df['dates'])).dt.days
print (df)
    number       dates  coord  datepond
AC      10  2018-07-10  11.54        97
AC      10  2018-07-11  11.19        96
AN       5  2018-07-12  69.40        95

尝试将一列日期减去另一个日期

1 个答案: