Question

我正在使用spring框架进行编程，实际上我创建了一个简单的Web应用程序，但是有时我会得到答案，而有时我会出错

spring-mvc-demo-servlet.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xsi:schemaLocation="
        http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context.xsd
        http://www.springframework.org/schema/mvc
        http://www.springframework.org/schema/mvc/spring-mvc.xsd">

    <!-- Step 3: Add support for component scanning -->
    <context:component-scan base-package="com.luv2code.springdemo/home" />

    <!-- Step 4: Add support for conversion, formatting and validation support -->
    <mvc:annotation-driven/>

    <!-- Step 5: Define Spring MVC view resolver -->
    <bean
        class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/view/" />
        <property name="suffix" value=".jsp" />
    </bean>


</beans>

web.xml

xsi：schemaLocation =“ http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd” id =“ WebApp_ID”版本=“ 3.1”>

<display-name>Test</display-name>

<!-- Spring MVC Configs -->

<!-- Step 1: Configure Spring MVC Dispatcher Servlet -->
<servlet>
    <servlet-name>dispatcher</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring-mvc-demo-servlet.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<!-- Step 2: Set up URL mapping for Spring MVC Dispatcher Servlet -->
<servlet-mapping>
    <servlet-name>dispatcher</servlet-name>
    <url-pattern>/</url-pattern>
</servlet-mapping>

HomeController.java

package com.luv2code.springdemo.mvc;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;

@Controller
public class HomeController {

    @RequestMapping("/home")
    public String showPage() {
        return "main-menu";
    }
}

main-menu.jsp

<!DOCTYPE>
<html>

<body>

<h2>Spring MVC Demo - Home Page</h2>

</body>

</html>

Answer 1

我已经尝试过相同的代码了

<context:component-scan base-package="com.sample.springdemo" />

即包名

http://localhost:8081/Test/home可以正常工作。

如果需要的话，也请查看以下链接 HTTP Status 404 - on Eclipse with Tomcat

Answer 2

我遇到了同样的错误，解决方案是简单地查看 spring-mvc-demo-servlet.xml 文件中的组件扫描标记。您使用的是讲师的 com.luv2code，但您的 package name 不同。

警告：在名称为“ dispatcher”的DispatcherServlet中找不到带有URI [/ Test /]的HTTP请求的映射

2 个答案: