我需要限制/禁用用户,使其根据其 JoinOn 日期的输入选择一个 LeaveOn 日期。示例:如果用户在 JoinOn 日期中选择 2018/10/13 ,则用户将不能选择 LeaveOn 日期作为日期低于 2018年10月13日,即日期不能为 10/10/2018 。
以下是我的相同代码:
<script>
$(document).ready(function () {
$('#IsPresent').change(function () {
if ($(this).is(':checked')) {
$('#PresentPanel').hide();
$('#LeaveOn').val("@(DateTime.Today.ToString("MM/dd/yyyy"))");
}
else {
$('#PresentPanel').show();
}
});
$('#JoinOn').datetimepicker(
{
datepicker: true,
timepicker: false,
format: 'm/d/Y',
step: 30,
minDate: new Date(1965, 1 - 1, 1),
maxDate: new Date()
});
$('#LeaveOn').datetimepicker(
{
datepicker: true,
timepicker: false,
format: 'm/d/Y',
step: 30,
maxDate: new Date()
});
});
答案 0 :(得分:0)
假设您已选择日期选择器日期作为事件监听器,则只需添加以下代码即可
var LeaveOnSelectedDate = $('#LeaveOn').datepicker('getDate');
var JoinOnDate = $('#JoinOn').datepicker('getDate');
JoinOnDate.setHours(0,0,0,0);
LeaveOnSelectedDate.setHours(0,0,0,0);
if (LeaveOnSelectedDate <= JoinOnDate) {
console.log("Date is old or same day!");
} else {
console.log("Date is in future!");
}
答案 1 :(得分:0)
尝试
$(function(e) {
$('#JoinOn').datetimepicker({
datepicker: true,
timepicker: false,
format: 'd/m/Y',
maxDate: 0,
onSelectDate: function(ct, $i) {
$('#LeaveOn').datetimepicker('setOptions', {
minDate: ct
});
}
});
$('#LeaveOn').datetimepicker({
datepicker: true,
timepicker: false,
format: 'd/m/Y',
maxDate: 0
});
});
希望这会有所帮助