从列表字典创建数据框，忽略键

Question

我有一个像这样的列表字典

d = {'key1':['banana','apple','mango'],
     'key2':['banana','orange'],
     'key3':['apple','melon','orange','mango']}

现在，我想从中创建数据框。数据框必须看起来像这样

 'banana' | 'apple'  | 'mango' | NaN
 'banana' | 'orange' |   NaN   | NaN
 'apple'  | 'melon'  | 'orange'|'mango'

Answer 1

使用

d = {'key1':['banana','apple','mango'],
     'key2':['banana','orange'],
     'key3':['apple','melon','orange','mango']}

>>> pd.DataFrame(list(d.values()))

    0       1       2       3
0   banana  apple   mango   None
1   banana  orange  None    None
2   apple   melon   orange  mango

Answer 2

您要使用orient='index'查找from_dict：

pd.DataFrame.from_dict(d, orient='index')

           0       1       2      3
key1  banana   apple   mango   None
key2  banana  orange    None   None
key3   apple   melon  orange  mango

如果要数字索引：

pd.DataFrame.from_dict(d, orient='index').reset_index(drop=True)

        0       1       2      3
0  banana   apple   mango   None
1  banana  orange    None   None
2   apple   melon  orange  mango