Question

我有很多国家，每个国家我都有很多球队。

团队控制器中的GetTeam端点检索单个Team及其相关的Nation。通过LINQ，查询是这样的：

Context.Teams.Include(t => t.Nation).First(t => t.Id.Equals(__id))

生成的JSON是我想要的：

{"team":{"name":"Team1","nation":{"id":1,"name":"Nation1"}}

现在让我们删除Team和Nation模型中的“名称”属性，并使用Translation创建新的模型关系。

我现在想要的是检索相同的JSON，但根据区域性使用不同的查询。发疯了，了解我如何通过包含来实现它。

如何在LINQ中编写此查询？

select * 
from Teams inner join 
Translations TeamTr on Teams.id = TeamTr .id and TeamTr .culture = "IT" inner join 
Nations on Teams.nation_id = Nations.id inner join 
Translations NationTr on Nations .id = NationTr .id and NationTr .culture = "IT"

然后将结果数据构成为上面的JSON？

Answer 1

例如：

(from team in Context.Teams
join teamTr in Context.Translations on team.id equals teamTr.id
join nation in Context.Nations on team.nation_id equals nations.id
join nationTr in Context.Translations on nation.id equals nationTr.id
where teamTr.culture == "IT" && nationTr.culture == "IT"
select new 
{
   teamName = team.name,
   nationName = nation.name

}).ToList();

Answer 2

很好抓tdayi。

首先，我创建了一个新类，它将作为linq结果的容器：

public class TeamDetailLinqDto
{
    public Team Team { get; set; }
    public Translation TeamTranslation { get; set; }
    public Nation Nation { get; set; }
    public Translation NationTranslation { get; set; }
}

这是linq查询：

    public IQueryable<TeamDetailLinqDto> GetTeams()
    {
        var result = from team in Context.Teams
                     join teamTranslation in Context.Translations on
                         new { Id = team.Id, Locale = "IT" }
                         equals new { Id = teamTranslation.EntityId, Locale = teamTranslation.Locale }
                     join nation in Context.Nations on team.NationId equals nation.Id
                     join nationTranslation in Context.Translations on
                         new { Id = nation.Id, Locale = "IT" }
                         equals new { Id = nationTranslation.EntityId, Locale = nationTranslation.Locale }
                     select new TeamDetailLinqDto
                     {
                         Team = team,
                         TeamTranslation = teamTranslation,
                         Nation = nation,
                         NationTranslation = nationTranslation
                     };

        return result;
    }

加入时包含其他参数

2 个答案: