我的结构数组仅显示最后一个输入-C ++

时间:2018-10-14 16:13:15

标签: arrays structure

因此,我尝试使用结构数组,您在其中输入自己的值到每个变量中。它的总体思路是,我希望用户输入5个不同的员工姓名,ID和年薪。该程序旨在输出结构数组。

但是,我的问题是,当我尝试输出数组时,输出似乎只显示数组的最后一个元素5倍。

感谢所有帮助!

p.s。不用担心平均功能,我想自己找出一个。

    #include <iostream>
#include <cstdlib>
#include <string>

using namespace std;

struct emp
{
    char empName[25];
    int id;
    float salary;
};

struct emp employee[5];

struct emp *getData();
void printData(struct emp employee[]);


int main()
{   
    cout << "Enter employee name, ID and Annual Salary: " << endl;
    struct emp *p;
    p = getData();


    printData(employee);


}

struct emp *getData()
{
    for (int i = 0; i < 5; i++)
    {
        cout << "Employee " << i + 1 << " name: ";
        cin >> employee->empName;
        cout << "Employee " << i+1 << " ID: ";
        cin >> employee->id;
        cout << "Employee " << i+1 << " Annual Salary: ";
        cin >> employee->salary;
        cin.ignore();
        cout << endl;
    }

    return employee;
}

void printData(struct emp employee[])
{
    for (int i = 0; i < 5; i++)
    {
        cout << "Employee " << i + 1 << ": " << employee->empName << " - " << employee->id << ", Annual Salary: " <<
            employee->salary << endl;
    }
}

//double getAverage(struct emp[], int)
//{
//
//}

输出

Enter employee name, ID and Annual Salary:
Employee 1 name: Ian
Employee 1 ID: 2345
Employee 1 Annual Salary: 12345

Employee 2 name: John
Employee 2 ID: 2345
Employee 2 Annual Salary: 23456

Employee 3 name: Carla
Employee 3 ID: 23452
Employee 3 Annual Salary: 2345

Employee 4 name: Chloe
Employee 4 ID: 12345
Employee 4 Annual Salary: 2345

Employee 5 name: Josh
Employee 5 ID: 234
Employee 5 Annual Salary: 12345

Employee 1: Josh - 234, Annual Salary: 12345
Employee 2: Josh - 234, Annual Salary: 12345
Employee 3: Josh - 234, Annual Salary: 12345
Employee 4: Josh - 234, Annual Salary: 12345
Employee 5: Josh - 234, Annual Salary: 12345
Press any key to continue . . .

1 个答案:

答案 0 :(得分:0)

您没有使用任何数组块,因此所有输入都进入第一个,所有输出都来自第一个。

for (int i = 0; i < 5; i++)
    {
        cout << "Employee " << i + 1 << " name: ";
        cin >> employee[i].empName;
        cout << "Employee " << i+1 << " ID: ";
        cin >> employee[i].id;
        cout << "Employee " << i+1 << " Annual Salary: ";
        cin >> employee[i].salary;
        cin.ignore();
        cout << endl;
    }

    return employee;
}

void printData(struct emp employee[])
{
    for (int i = 0; i < 5; i++)
    {
        cout << "Employee " << i + 1 << ": " << employee[i].empName << " - " << employee[i].id << ", Annual Salary: " <<
            employee[i].salary << endl;
    }
}

这应该解决您的代码