Question

我需要模拟服务。我在模拟类时在ResponseEntity<?>中得到null。

需要模拟的方法：

public List<Expression> getExpression(String expressView, Localdate date) {

    List<Expression> =new ArrayList<>();
    Map<String, Object> uri = new HashMap<>();
    UriComponenetsBuilder build = 
        UriComponentsBuilder.fromHttpUrl("someUrl" + "/" + expressView);
    build.queryParam(someParameter, someParameter);
    build.queryParam(someParameter, someParameter);
    build.queryParam(someParameter, someParameter);

    HttpHeaders header = new HttpHeaders();
    header.setContentType(MediaType.APPLICATION_JSON);
    RestClient client = new RestClient(
        build.build().encode.toUriString, HttpMethod.GET.Uri, header
    );

    ResponseEntity<?> resp = restC.SomeMethod(client);

    if (resp = !null) {
        //it goes to these line
    }

  }

在我的模拟方法中：

when(restC.SomeMethod(client)).thenReturn(resp);

因此，上述方法调用服务获取一些数据，获取expressView的值并另存为列表。当我嘲笑方法when(restC.SomeMethod(client)).thenReturn(resp);时，它命中了URL，但我作为响应resp获得的值为null。所以在这里，我将resp的值设为null。我检查了邮递员中的URL（someUrl）返回值。

如何模拟ResponseEntity<?>？

谢谢。

Answer 1

First, create a ResponseEntity object:

HttpHeaders header = new HttpHeaders();
header.setContentType(MediaType.APPLICATION_JSON);

ResponseEntity<?> responseEntity = new ResponseEntity<>(
    "some response body",
    header, 
    HttpStatus.OK // Or HttpStatus.ACCEPTED
);

Then build a mock:

when(restC.SomeMethod(client)).thenReturn(responseEntity);

Point to pay attention:

Avoid to use ResponseEntity inside @Service class. You should use ResponseEntity in @RestController class.

And you can Inject you @Service class using @Autowired annotation, like:

@RestController
public class YourClass {

    @Autowired
    private YourClassService yourClassService;

So:

@Service class will handle business or data objects and @RestController class will handle Response and Request objects. Thus we have Single Responsibility principle.

Some nice links:

希望这会有所帮助！

如何用通用类型模拟ResponseEntity <！-？->？

1 个答案: