如何使用Tomcat服务器在Jersey的RestAPI中更改URL

Question

我使用Tomcat服务器使用jersey框架创建了RestApi。但是现在我想更改URL以访问该api。
    http://localhost:8080/uproject/webapi/test/inox/seats?status=unreserved
上面是我现在正在访问的URL。我想将其更改为
http://localhost:8080/test/inox/seats?status=unreserved
我们如何实现它。我在这里包含我的xml文件。

<?xml version="1.0" encoding="UTF-8"?>
<!-- This web.xml file is not required when using Servlet 3.0 container,
 see implementation details 
http://jersey.java.net/nonav/documentation/latest/jax-rs.html -->
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" 
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
    <servlet-name>Jersey Web Application</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
    <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>org.maneesh.udaan.uproject</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
 </servlet>
 <servlet-mapping>
    <servlet-name>Jersey Web Application</servlet-name>
    <url-pattern>/webapi/*</url-pattern>
</servlet-mapping>  
</web-app>

我从/ test访问我的页面。