Question

无法弄清楚是什么问题，我想制作一个程序，该程序需要一行字符串，并按“ In”函数中的描述返回单词及其类型。

这是代码

def __init__(self):

    self.Action = "Action"
    self.Noun = "Noun"
    self.Shit = "Shit"
    self.Error = "Error"


    ACTION = ["Go","Kill","Jump"]
    NOUN = ["Lion","Building","World"]
    SHIT = ["shit","shit5"]






def Hard_worker(word):
    Action = "Action"
    Noun = "Noun"
    Shit = "Shit"
    Error = "Error"

    raw_data = word.lower()


    if raw_data in Action:
        return(Action,word)
    elif raw_data in Noun:
        return(Noun,word)
    elif raw_data in Shit:
        return(Shit,word)
    else:
        return(Error,word)

def scan(line):
    print"Scanning the line %r" % line

    words = line.split()
    return map(Hard_worker(words))


scan("Go Kill Jump")

任何帮助将不胜感激。

Answer 1

return map(Hard_worker(words))

那不是您所说的map。函数和迭代器必须是两个参数。

return map(Hard_worker, words)

您还可以在此处使用列表理解。

return [Hard_worker(word) for word in words]

“列表”对象没有属性“较低”

1 个答案: