我是boost::spirit
的新手,正在尝试使用x3编写一个简单的解析器。
我遇到了我无法解释的错误。
由于某种原因,我收到关于boost::spirit::x3::unused_type
的错误。
当我在下面标记的行中删除支流星时,错误消失。
其他克利恩星似乎还不错(由于某种原因)。
这是我的代码:
#include <string>
#include <iostream>
#include <boost/spirit/home/x3.hpp>
namespace x3 = boost::spirit::x3;
int main()
{
std::string str = "qqq::qqq::qqq";
auto begin = str.begin(), end = str.end();
bool r = x3::parse(begin, end,
( (x3::alpha | '_') >> *(x3::alnum | '_')) >>
* //this line is the problem
("::" >> (x3::alpha | '_') >> *(x3::alnum | '_'))
); // is supposed to match str
if (r && std::distance(begin,end) < 1)
{
std::cout << "Parsing succeeded\n";
}
else
{
std::cout << "Parsing FAILED\n";
std::cout << "r " << r << " d " << std::distance(begin,end) << "\n";
}
return 0;
}
这是错误:
/usr/include/boost/spirit/home/x3/core/detail/parse_into_container.hpp:254:22: error: ‘const struct boost::spirit::x3::unused_type’ has no member named ‘empty’
254 | if (attr.empty())
| ~~~~~^~~~~
/usr/include/boost/spirit/home/x3/core/detail/parse_into_container.hpp:259:22: error: ‘const struct boost::spirit::x3::unused_type’ has no member named ‘insert’
259 | attr.insert(attr.end(), rest.begin(), rest.end());
| ~~~~~^~~~~~
/usr/include/boost/spirit/home/x3/core/detail/parse_into_container.hpp:259:34: error: ‘const struct boost::spirit::x3::unused_type’ has no member named ‘end’
259 | attr.insert(attr.end(), rest.begin(), rest.end());
| ~~~~~^~~
/usr/include/boost/spirit/home/x3/core/detail/parse_into_container.hpp:259:46: error: ‘const struct boost::spirit::x3::unused_type’ has no member named ‘begin’
259 | attr.insert(attr.end(), rest.begin(), rest.end());
| ~~~~~^~~~~
/usr/include/boost/spirit/home/x3/core/detail/parse_into_container.hpp:259:60: error: ‘const struct boost::spirit::x3::unused_type’ has no member named ‘end’
259 | attr.insert(attr.end(), rest.begin(), rest.end());
| ~~~~~^~~
我在使用Boost 1.65.1的Ubuntu 18.04上。 我读了这篇(https://stackoverflow.com/a/49121776/2359966)帖子,其中描述了类似的问题。
是否可以在不更改系统软件包的情况下解决或避免此问题?
答案 0 :(得分:2)
不,这只是一个已修复的错误。
无论如何,像x3::alpha | '_'
这样的语法构造不会显示您所需的内容,因为文字 '_'
不会显示任何属性。
因此,实际上,您可能只想使用raw[]
进行简化:
auto ident = x3::raw [ x3::lexeme [ (x3::alpha | '_') >> *(x3::alnum | '_') ]
接下来,您可以匹配多个::
限定的标识符:
x3::raw [ ident >> * ("::" >> ident) ]
顺便说一句,完全等同于
x3::raw [ ident % "::") ]
请参见
分配属性
#include <boost/spirit/home/x3.hpp>
#include <iostream>
#include <iomanip>
#include <string>
namespace x3 = boost::spirit::x3;
int main() {
std::string str = "foo::_bar::qux_1";
auto begin = str.begin(), end = str.end();
auto ident = x3::raw [ x3::lexeme [ (x3::alpha | '_') >> *(x3::alnum | '_') ] ];
std::vector<std::string> qualified;
bool r = x3::parse(begin, end, ident % "::", qualified);
if (r && begin==end) {
std::cout << "Parsing succeeded\n";
for (auto& el : qualified) {
std::cout << " element " << std::quoted(el) << "\n";
}
} else {
std::cout << "Parsing FAILED\n";
}
std::cout << std::boolalpha << r << " " << std::quoted(std::string(begin, end)) << "\n";
}
打印:
Parsing succeeded
element "foo"
element "_bar"
element "qux_1"
true ""
语法被简化为
std::vector<std::string> qualified;
bool r = x3::parse(begin, end, ident % "::", qualified);
通常这是一个好兆头。