Question

我的oracle数据库表'my_table'带有以下示例行-

Case_ID Start_Date  End_Date    STATUS
123     01/10/2018  03/10/2018  Close
124     02/10/2018              Open
125     03/10/2018  05/10/2018  Close
126     04/10/2018              Open
127     05/10/2018  07/10/2018  Close
128     06/10/2018              Open
129     07/10/2018  09/10/2018  Close
130     08/10/2018  10/10/2018  Close
131     09/10/2018              Open

我想获取以下格式的输出-

Week_No  Inflow Outflow  Total_Backlog
40       7       4       3
41       2       1       4

如何使用一个查询将以下三个查询组合在一起以获得上述格式的所需输出？

 SELECT to_char(Start_Date,'IW') Week_No, count(CASE_ID) as Inflow 
   FROM my_table;

 SELECT to_char(End_Date,'IW') Week_No, count(CASE_ID) as Outflow  
   FROM my_table 
  WHERE status='Close';

 SELECT to_char(Start_Date,'IW') Week_No, count(CASE_ID) as Total_Backlog  
   FROM my_table 
  WHERE status <> 'Close';

Answer 1

您可以使用：

select week_no, sum(nvl(Inflow,0)) as Inflow, 
                sum(nvl(Outflow,0)) as Outflow, 
                sum(nvl(Total_Backlog,0)) as Total_Backlog
  from               
   (
    select to_char(Start_Date,'IW') Week_No, 
           count(CASE_ID) as Inflow,
           ( case when STATUS != 'Close' then count(CASE_ID) end ) as Total_Backlog,
           null Outflow 
      from my_table
     group by to_char(Start_Date,'IW'), status
     union all
    select to_char(End_Date,'IW') Week_No, 
           null as Inflow, null as Total_Backlog,
           ( case when STATUS = 'Close' then count(CASE_ID) end ) as Outflow 
      from my_table
     where End_Date is not null
     group by to_char(End_Date,'IW'), status
    ) 
 group by week_no
 order by week_no;

 WEEK_NO    INFLOW  OUTFLOW TOTAL_BACKLOG
    40         7       3          3
    41         2       2          1

Rextester Demo

或者您可能会喜欢一些不同的方式：

select week_no, sum(nvl(Inflow,0)) as Inflow, 
                sum(nvl(Outflow,0)) as Outflow, 
                sum(nvl(Total_Backlog,0)) as Total_Backlog
  from               
   (
    select to_char(Start_Date,'IW') Week_No, 
           count(CASE_ID) as Inflow,
           count( case when STATUS != 'Close' then CASE_ID end ) as Total_Backlog,
           null Outflow 
      from my_table
     group by to_char(Start_Date,'IW')
     union all
    select to_char(End_Date,'IW') Week_No, 
           null as Inflow, null as Total_Backlog,
           count( case when STATUS = 'Close' then CASE_ID end ) as Outflow 
      from my_table
     where End_Date is not null 
     group by to_char(End_Date,'IW')
    ) 
 group by week_no
 order by week_no;

 WEEK_NO    INFLOW  OUTFLOW TOTAL_BACKLOG
    40         7       3          3
    41         2       2          1

Oracle SQL查询以获取每周记录

1 个答案: