Question

我是编码新手。请对我好一点。我负责创建一个程序来比较两个排球的得分。要赢得排球比赛，一支球队必须获得25分。但是球队也必须以2获胜。这两支球队将进行5场比赛。

程序应从用户那里接受每个团队一次比赛的得分。如果用户在任何时候输入的分数违反25分规则或“以2获胜”规则，请在屏幕上打印错误，然后让用户再次输入两个分数。

当用户输入完分数后，打印出赢得比赛的球队，即赢得比赛最多的球队。

您必须在此分配中使用数组和循环。

我的程序仅对数组中的第一组分数进行评分。 如何使它存储所有五组分数？

public static void main(String[] args) {
        int team1[];
        int team2[];
        team1=new int[5];
        team2=new int[5];
        int counter1=0;
        int counter2=0;
        int k = 0;


        for (int i=0;i<=4;i++){       
        Scanner scanint = new Scanner(System.in);
        System.out.println("Enter the number of points Team 1 earned in Match " + (i+1));
        team1[i] = scanint.nextInt();
        System.out.println("Enter the number of points Team 2 earned in Match " + (i+1));
        team2[i] = scanint.nextInt();

////////////////////////////////////////////
        if (team1[i] < 25 & team2[i] < 25){
            System.out.println("That cannot be. One team must get at least 25 points. Please re-enter the data.");
            System.out.println("Enter the number of points Team 1 earned in Match " + (i+1));
        team1[i] = scanint.nextInt();
        System.out.println("Enter the number of points Team 2 earned in Match " + (i+1));
        team2[i] = scanint.nextInt();
        }



        else if (team1[i] - team2[i] < 2 || team2[i] - team1[i] < 2){
           System.out.println("That can't be. One team must win by at least two points. Please re-enter the data.");
            System.out.println("Enter the number of points Team 1 earned in Match " + (i+1));
        team1[i] = scanint.nextInt();
        System.out.println("Enter the number of points Team 2 earned in Match " + (i+1));
        team2[i] = scanint.nextInt();
        }

        else {
            System.out.println("Enter the number of points Team 1 earned in Match " + (i+1));
        team1[i] = scanint.nextInt();
        System.out.println("Enter the number of points Team 2 earned in Match " + (i+1));
        team2[i] = scanint.nextInt();
        }


        /////////////////////////////////////////////

        if (team2[i] < team1[i]){
           counter1++;}
       else{ counter2++;}

    }
     if (counter1 > counter2)  {
      System.out.println("Team 1 has won the game.");}
      else{
              System.out.println("Team 2 has won the game.");
              }

Answer 1

好吧，我看到的完成游戏规则很少：

任何一支球队都不能得负分。
至少一支球队必须获得25分以上的得分。
一个团队的得分不能高于25，除非该得分恰好是另一个团队的上下两个得分。

那么，我们该怎么做呢？每个规则带有一些if语句。对于第一个规则：

if ((team1 < 0) || (team2 < 0)) {
    System.err.println("A score cannot be negative!");
    i--;
    continue;
}

第二条规则：

if ((team1 < 25) && (team2 < 25)) {
    System.err.println("At least one team has to have 25 or more points!");
    i--;
    continue;
}

对于第三条规则（可以使用if将其转换为一条&&语句，但是我使它变得更易于理解）：

if ((team1 > 25) || (team2 > 25)) {
    if ((team1 - team2 != 2) && (team2 - team1 != 2)) {
        System.err.println("If a team has more than 25 points, the other team must be two points away from it!");
        i--;
        continue;
    }
}

请注意，continue;意味着转到您所在循环的下一个迭代。因此，您使用i--;转到上一个迭代，而使用{{ 1}}。这是一个技巧，可让您重新启动所在循环的当前迭代。

此外，除非我在初始数据输入循环之外的某个地方使用了分数，否则我不会使用数组（尽管您应遵循分配规则并始终使用它们）。我会立即指出游戏的得分何时无效，并且会在continue;和int team1Wins = 0;等一些变量中跟踪两支球队的获胜情况。

Java排球计分程序数组和循环

1 个答案: