我如何生成一个数组，该数组包含10/1和1/10之间的10个随机分数。我已经编码了Java类Rational来完成这项工作。
在Rational Class中，定义了一些基本方法。请上课。
public class Rational {
// Private instance variables
private int numerator;
private int denominator;
// Constructor
public Rational(){
this.numerator = 0;
this.denominator = 1;
}
// Overloaded constructor
public Rational(int num, int den){
this.numerator = num;
this.denominator = den;
reduce();
}
// Getter method for numerator
public int getNumerator(){
return this.numerator;
}
// Getter method for denominator
public int getDenominator(){
return this.denominator;
}
// Getter method for double
public double toDouble(){
return(double)this.numerator/this.denominator;
}
// Getter method for string
public String toString(){
if(denominator == 0){
return "ERROR";
}
if(denominator == 1){
return this.numerator + "";
}
else {
return this.numerator + "/" + this.denominator;
}
}
// Void method for negate
public void negate(){
this.numerator = -1 * numerator;
}
// Void method for invert
public void invert(){
int flip = this.numerator;
this.numerator = this.denominator;
this.denominator = flip;
}
// Value method for addition
public Rational add(Rational test){
this.numerator = (numerator * denominator) + (test.getDenominator() * test.getNumerator());
this.denominator = test.getDenominator() * denominator;
return new Rational(numerator,denominator);
}
// Euclid's GCD
private static int gcd(int x, int y){
if (0 == y){
return x;
}
else {
return gcd(y,x%y);
}
}
// Void method for reduce, using GCD
public void reduce(){
int div;
div = Rational.gcd(numerator, denominator);
this.numerator = numerator/div;
this.denominator = denominator/div;
}
// *Bonus* value method for multiplication
public Rational multiply(Rational test){
int numx = this.numerator * test.getNumerator();
int denx = this.denominator * test.getDenominator();
return new Rational(numx, denx);
}
}
但是我在创建逻辑以生成具有特定范围的随机分数时遇到问题...
答案 0 :(得分：0)
您可以遵循此简单策略。您知道您的分数介于1/10和10之间，
1/10 这暗示着 den / 10 因此，首先随机修复窝（从0到9随机选择）。解决此问题后，请从den / 10到10 * den