Matplotlib用Python代替用户输入变量

时间:2018-10-12 15:04:25

标签: python matplotlib

我正在尝试用python编写一个程序,该程序将接受用户输入以在matplotlib中设置甜甜圈饼图的颜色。 这是我目前正在使用的东西:

#3 ring 3 - Factors
mypie4, _ =ax.pie(factor_size, radius=5-1.4, colors=[a(0.85), a(0.85), 
                                                     g(0.0), a(0.85), 
                                                     g(0.0), 
                                                     b(0.7), b(0.7), b(0.7),
                                                     c(0.85), c(0.85), 
                                                     c(0.85), c(0.85), 
                                                     g(0.0), g(0.0),
                                                     d(0.85), d(0.85), 
                                                     g(0.0)])
plt.setp(mypie4, width=.2, edgecolor='black')
plt.margins(0,0)

这就是我想发生的事情:

## Show menu ##
print (30 * '-')
print ("   Color Choices for First Quadrant")
print (30 * '-')
print ("1. Blue")
print ("2. Orange")
print ("3. Green")
print ("4. Purple")
print (30 * '-')

## Get input ###
choice = raw_input('Enter your choice [1-4] : ')

### Convert string to int type ##
choice = int(choice)

### Take action as per selected menu-option ###
if choice == 1:
    user_color = [plt.cm.Blues(0.75)]
elif choice == 2:
    user_color = [plt.cm.Oranges(0.75)]
elif choice == 3:
    user_color = [plt.cm.Greens(0.75)]
elif choice == 4:
    user_color = [plt.cm.Purples(0.75)]
else:    ## default ##
    print ("Invalid number. Try again...")    


#3 ring 3 - Factors
mypie4, _ =ax.pie(factor_size, radius=5-1.4, colors=[[user_color], 
                                                     [user_color], 
                                                    [user_color], 
                                                     [user_color], 
                                                     [user_color], 
                                                     b(0.7), b(0.7), b(0.7),
                                                     c(0.85), c(0.85), 
                                                     c(0.85), c(0.85), 
                                                     g(0.0), g(0.0),
                                                     d(0.85), d(0.85), 
                                                     g(0.0)])
plt.setp(mypie4, width=.2, edgecolor='black')
plt.margins(0,0)

我不知道如何将变量调用到ax.pie的colors属性中。使用这种格式,我可以对其他象限执行相同的操作。随附的是我手动制作的最终照片。我希望能够自动产生这些颜色。donut color quadrant wheel

1 个答案:

答案 0 :(得分:0)

您需要将颜色放入单个阵列中。您生成了多个数组,每个数组都有一个值。

首先,您需要将所有象限的用户输入保存到单个数组中。因此,您可以使用以下功能:

def getQuadrantColor(colorList, quadrantName):
    print (30 * '-')
    print ("   Color Choices for {} Quadrant".format(quadrantName))
    print (30 * '-')
    print ("1. Blue")
    print ("2. Orange")
    print ("3. Green")
    print ("4. Purple")
    print (30 * '-')
    ## Get input ###
    choice = raw_input('Enter your choice [1-4] : ')

    ### Convert string to int type ##
    choice = int(choice)

    ### Take action as per selected menu-option ###
    if choice == 1:
        colorList.append(plt.cm.Blues(0.75))
    elif choice == 2:
        colorList.append(plt.cm.Oranges(0.75))
    elif choice == 3:
        colorList.append(plt.cm.Greens(0.75))
    elif choice == 4:
        colorList.append(plt.cm.Purples(0.75))
    else:    ## default ##
        print ("Invalid number. Try again...") 
        getQuadrantColor(colorList, quadrantName)

您现在可以像使用此功能

colorList = []
quadrants = ["First", "Second", "Third", "Fourth"]
for quadrant in quadrants:
    getQuadrantColor(colorList, quadrant)

现在您已经获得了所有颜色信息,并且可以创建饼图

mypie4, _ =ax.pie(factor_size, radius=5-1.4, colors=colorList)
plt.setp(mypie4, width=.2, edgecolor='black')
plt.margins(0,0)