AXAccessQueue类在...和...中均实现。将使用两者之一

时间:2018-10-12 13:36:48

标签: ios xcode10

Xcode10运行一个空白项目。我选择Simulator iPhoneXR。控制台打印如下

Class AXAccessQueue is implemented in both...and...One of the two will be used.
Class AXAccessQueueTimer is implemented in both...and...One of the two will be used.
[AXMediaCommon] Unable to look up screen scale
[AXMediaCommon] Unexpected physical screen

我更改了模拟器iPhone6。控制台会打印

libMobileGestalt  MobileGestalt.c:890: MGIsDeviceOneOfType is not supported on this platform.

如何产生这种现象?以及如何解决问题?

感谢您的回答。

0 个答案:

没有答案