将自动增量添加到MS Access 2016中的现有查询(不是表)

时间:2018-10-12 11:01:21

标签: ms-access auto-increment

我在MS ACCESS 2016中有查询,需要向其中添加自动编号。基本上,查询输出结果是一列数据,我想向此输出添加新列,其数字从1开始到查询输出的行数。我不想从查询输出中创建一个新表。有没有办法在查询中做到这一点?我设法添加了一个仅具有标量值的新ID列,但是我需要的是在此处自动递增。有什么想法吗?

SELECT qry.ColA, 1 AS ID
FROM qry;

1 个答案:

答案 0 :(得分:1)

是的,请使用我文章中的 RowNumber 函数:

Sequential Rows in Microsoft Access

GitHub上的完整代码:VBA.RowNumbers

' Builds consecutive row numbers in a select, append, or create query
' with the option of a initial automatic reset.
' Optionally, a grouping key can be passed to reset the row count
' for every group key.
'
' Usage (typical select query):
'   SELECT RowNumber(CStr([ID])) AS RowID, *
'   FROM SomeTable
'   WHERE (RowNumber(CStr([ID])) <> RowNumber("","",True));
'
' Usage (with group key):
'   SELECT RowNumber(CStr([ID]), CStr[GroupID])) AS RowID, *
'   FROM SomeTable
'   WHERE (RowNumber(CStr([ID])) <> RowNumber("","",True));
'
' The Where statement resets the counter when the query is run
' and is needed for browsing a select query.
'
' Usage (typical append query, manual reset):
' 1. Reset counter manually:
'   Call RowNumber(vbNullString, True)
' 2. Run query:
'   INSERT INTO TempTable ( [RowID] )
'   SELECT RowNumber(CStr([ID])) AS RowID, *
'   FROM SomeTable;
'
' Usage (typical append query, automatic reset):
'   INSERT INTO TempTable ( [RowID] )
'   SELECT RowNumber(CStr([ID])) AS RowID, *
'   FROM SomeTable
'   WHERE (RowNumber("","",True)=0);
'
' 2018-08-23. Gustav Brock, Cactus Data ApS, CPH.
'
Public Function RowNumber( _
    ByVal Key As String, _
    Optional ByVal GroupKey As String, _
    Optional ByVal Reset As Boolean) _
    As Long

    ' Uncommon character string to assemble GroupKey and Key as a compound key.
    Const KeySeparator      As String = "¤§¤"
    ' Expected error codes to accept.
    Const CannotAddKey      As Long = 457
    Const CannotRemoveKey   As Long = 5

    Static Keys             As New Collection
    Static GroupKeys        As New Collection

    Dim Count               As Long
    Dim CompoundKey         As String

    On Error GoTo Err_RowNumber

    If Reset = True Then
        ' Erase the collection of keys and group key counts.
        Set Keys = Nothing
        Set GroupKeys = Nothing
    Else
        ' Create a compound key to uniquely identify GroupKey and its Key.
        ' Note: If GroupKey is not used, only one element will be added.
        CompoundKey = GroupKey & KeySeparator & Key
        Count = Keys(CompoundKey)

        If Count = 0 Then
            ' This record has not been enumerated.
            '
            ' Will either fail if the group key is new, leaving Count as zero,
            ' or retrieve the count of already enumerated records with this group key.
            Count = GroupKeys(GroupKey) + 1
            If Count > 0 Then
                ' The group key has been recorded.
                ' Remove it to allow it to be recreated holding the new count.
                GroupKeys.Remove (GroupKey)
            Else
                ' This record is the first having this group key.
                ' Thus, the count is 1.
                Count = 1
            End If
            ' (Re)create the group key item with the value of the count of keys.
            GroupKeys.Add Count, GroupKey
        End If

        ' Add the key and its enumeration.
        ' This will be:
        '   Using no group key: Relative to the full recordset.
        '   Using a group key:  Relative to the group key.
        ' Will fail if the key already has been created.
        Keys.Add Count, CompoundKey
    End If

    ' Return the key value as this is the row counter.
    RowNumber = Count

Exit_RowNumber:
    Exit Function

Err_RowNumber:
    Select Case Err
        Case CannotAddKey
            ' Key is present, thus cannot be added again.
            Resume Next
        Case CannotRemoveKey
            ' GroupKey is not present, thus cannot be removed.
            Resume Next
        Case Else
            ' Some other error. Ignore.
            Resume Exit_RowNumber
    End Select

End Function