我面临一个必须将Groovy对象序列化为xml的问题。
这是我用来序列化的代码:
static <T> Element serializeGenericObjectToXmlTypeElement(T object, boolean removeDeclaration = false) {
JAXBContext jc = JAXBContext.newInstance(object.getClass())
Marshaller marshaller = jc.createMarshaller()
if (removeDeclaration) {
marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true)
}
Writer writer = new StringWriter()
marshaller.marshal(object, writer)
def xmlString = writer.toString()
def stringReader = new StringReader(xmlString)
def builder = new SAXBuilder()
def doc = builder.build(stringReader)
def elem = doc.getRootElement()
MyXMLFormatter xmlFormatter = new MyXMLFormatter(elem)
Element element2 = xmlFormatter.formatXml(elem)
return element2
}
在marhsaller.marshal(对象,作家)上失败
我正在发送一个大的嵌套对象,但我认为它在以下对象(其中元素为org.jdom.element,版本1.13)中失败:
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "RapportIndholdType", propOrder = [
"any"
])
class RapportIndholdType {
@XmlAnyElement
Element any
}
由于我收到以下错误消息:
[com.sun.istack.internal.SAXException2: class org.jdom.Element nor any of its super class is known to this context.
javax.xml.bind.JAXBException: class org.jdom.Element nor any of its super class is known to this context.]
当我查看xml时,生成的最后一部分是这样的:
<ns5:RapportIndhold
挑战在于,任何元素,在任何情况下都可以是任何xml(转换为jdom元素),因此我需要能够编组jdom元素。
我尝试使用@XmlAnyElement(lax = true),但这没用。
有人知道我如何使它工作的解决方案吗?