我需要在google piechart上显示一些数据,并且我必须使用2个表来实现此目的。表名称是身份验证和代理详细信息,并且这两个表都有相似的列,称为“ agentlogin”。 agentdetails具有代理的所有数据,通过身份验证,我可以获取已注册的代理的数量。我需要从也显示在身份验证中的agentdetails中获取agentlogin的数据,我想按skill2列对它们进行分组。
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.8.3/jquery.min.js"></script>
<script type="text/javascript" src="https://www.google.com/jsapi"></script>
<script type="text/javascript">
google.load("visualization", "1", { packages: ["corechart"] });
google.setOnLoadCallback(drawChart);
function drawChart() {
var options = {
title: 'Registration'
};
$.ajax({
type: "POST",
url: "adminrep.aspx/GetChartData",
data: '{}',
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function (r) {
var data = google.visualization.arrayToDataTable(r.d);
var chart = new google.visualization.PieChart($("#chart")[0]);
chart.draw(data, options);
},
failure: function (r) {
alert(r.d);
},
error: function (r) {
alert(r.d);
}
});
}
</script>
public static List<object> GetChartData()
{
string query = "SELECT authentication.agentlogin, agentdetails.skill2, COUNT(authentication.agentlogin) TotalRegistration FROM agentdetails ";
query += " INNER JOIN authentication ON agentdetails.agentlogin = authentication.agentlogin WHERE agentdetails.location = 'PNQ10-Pune' GROUP BY skill2";
string MyConString = ConfigurationManager.ConnectionStrings["connStr"].ConnectionString;
List<object> chartData = new List<object>();
chartData.Add(new object[]
{
"skill2", "TotalRegistration"
});
using (MySqlConnection con = new MySqlConnection(MyConString))
{
using (MySqlCommand cmd = new MySqlCommand(query))
{
cmd.CommandType = CommandType.Text;
cmd.Connection = con;
con.Open();
using (MySqlDataReader sdr = cmd.ExecuteReader())
{
while (sdr.Read())
{
chartData.Add(new object[]
{
sdr["skill2"], sdr["TotalRegistration"]
});
}
}
con.Close();
return chartData;
}
}
}
表
我该如何完成?预先感谢。
答案 0 :(得分:2)
如果您想计算是否进行了身份验证,那么,您需要一个 LEFT 联接才能从第一个表中获取所有结果,而不仅仅是两个表中都出现的结果>
如果表之间的关系是1到1,那么每个座席将只出现一次,则左联接上将不会出现重复的重新填充,并且重新填充应类似于您已经到达的重新填充。
请注意,总注册数量当然仅是已注册的代理商,而不是所有代理商的注册数量:
SELECT
ad.skill2,
SUM(IF( auth.agentlogin IS NULL, 1,0)) AS TotalRegistration
FROM agentdetails ad
LEFT JOIN authentication auth ON ad.agentlogin = auth.agentlogin
WHERE ad.location = 'PNQ10-Pune'
GROUP BY
ad.skill2
您的原始查询:
SELECT authentication.agentlogin, agentdetails.skill2, COUNT(authentication.agentlogin) TotalRegistration FROM agentdetails
INNER JOIN authentication ON agentdetails.agentlogin = authentication.agentlogin WHERE agentdetails.location = 'PNQ10-Pune' GROUP BY skill2;
希望有帮助