每5秒将连续的DateTime值插入表中

时间:2018-10-12 08:13:41

标签: sql-server tsql datetime while-loop datetimeoffset

说我有一个这样的表:

CREATE TABLE table1
(
    CreatedAt   DAteTimeOffset  NULL
);

如何在while循环中插入该表500行,并每5秒发送一次日期?我希望我的结果像这样:

2018-10-08 05:00:00.0000000 +00:00
2018-10-08 05:00:05.0000000 +00:00
2018-10-08 05:00:10.0000000 +00:00
2018-10-08 05:00:15.0000000 +00:00
2018-10-08 05:00:20.0000000 +00:00
2018-10-08 05:00:25.0000000 +00:00
2018-10-08 05:00:30.0000000 +00:00
2018-10-08 05:00:35.0000000 +00:00
2018-10-08 05:00:40.0000000 +00:00
2018-10-08 05:00:45.0000000 +00:00
2018-10-08 05:00:50.0000000 +00:00
2018-10-08 05:00:55.0000000 +00:00
2018-10-08 05:01:00.0000000 +00:00
2018-10-08 05:01:05.0000000 +00:00
2018-10-08 05:01:10.0000000 +00:00
2018-10-08 05:01:15.0000000 +00:00

以此类推...

我在这里有一个while循环,但是我不知道如何实现每5秒插入一次具有值的连续行。

DECLARE
    @i int = 0

WHILE @i < 500
BEGIN
    INSERT INTO table1
    (CreatedAt)
    VALUES
    (?)
END

2 个答案:

答案 0 :(得分:4)

尝试使用基于集合的方法。通常更快:

WITH N AS --generate 500 rows (1..500)
(
    SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 1)) N
    FROM (VALUES (1),(2),(3),(4),(5)) A(A)
    CROSS JOIN (VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) B(B)
    CROSS JOIN (VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) C(C)
)
INSERT INTO table1 SELECT DATEADD(SECOND, (N-1)*5, SYSDATETIME()) FROM N

如果确实需要循环(不推荐使用),则可以使用以下代码:

DECLARE @i int = 0;
DECLARE @d DAteTimeOffset = SYSDATETIME();
WHILE @i<500
BEGIN
    INSERT table1 VALUES (@d);
    SET @d = DATEADD(second, 5, @d);
    SET @i += 1;
END

答案 1 :(得分:0)

我认为Zohar就是这个解决方案

declare @t table (CreatedAt datetime)

insert into @t 
select top 500 
       dateadd(second, (row_number() over (order by @@spid ) - 1) * 5, sysdatetime()) 
from   sys.objects 
  --cross join sys.objects a cross join sys.objects b 

select * from @t