Question

我一直在尝试为ESP8266创建浅睡眠，在其中我想使系统睡眠并触发GPIO输入的唤醒（就像按下按钮一样）。

它的代码非常简单

#include <ESP8266WiFi.h> 
#include <Wire.h> 
#define PIN 5

extern "C"
{
  #include "gpio.h"
}

extern "C"
{
  #include "user_interface.h"
}


int wifi_connection_attempts;
const char * password = "PASSWORD";
const char * ssid = "SSID";
bool isAsleep = false;
void setup()
{
  Serial.begin(115200);
  delay(100);
  Serial.println("Setup!");
  wifi_fpm_set_sleep_type(LIGHT_SLEEP_T); // set sleep type, the above         posters wifi_set_sleep_type() didnt seem to work for me although it did let me     compile and upload with no errors 
  WiFi.mode(WIFI_STA);
  connect_to_wifi();
  gpio_pin_wakeup_enable(digitalPinToInterrupt(PIN), GPIO_PIN_INTR_ANYEDGE);
  gpio_intr_handler_register(wakeup, NULL);
  delay(5000);
  Serial.println("Going to Sleep!");
  sleep();
  delay(5000);
}

void connect_to_wifi()
{
  WiFi.begin(ssid, password);
  Serial.println("Connecting to WiFi..");
  while (WiFi.status() != WL_CONNECTED)
  {
    delay(500);
    Serial.print(".");
  }
  if (WiFi.status() == WL_CONNECTED)
  {
    Serial.println("Connected to the WiFi network");
  }
  wifi_fpm_set_sleep_type(LIGHT_SLEEP_T);
}

void sleep()
{
  Serial.println("Going to sleep");
  delay(1000);
  wifi_station_disconnect();
  Serial.println("WifiDisconnected");
  bool stopped;
  do {
    stopped = wifi_station_get_connect_status() == DHCP_STOPPED;
    if (!stopped)
    {
      Serial.println("dhcp not stopped?");
      delay(100);
    }
  } while (!stopped);
  Serial.println("---off...");
  wifi_set_opmode(NULL_MODE);
  wifi_set_sleep_type(MODEM_SLEEP_T);
  wifi_fpm_open();
  wifi_fpm_do_sleep(0xFFFFFFF);
}

void wakeup(uint32 interruptMask, void * arg)
{
  os_printf("Interrupted: %x\n", interruptMask);
  Serial.print("lastIntr:");
  Serial.println(system_get_time());
  gpio_intr_ack(interruptMask);
  Serial.println("Waking Up");
  wifi_fpm_do_wakeup();
  wifi_fpm_close();
  wifi_set_opmode(STATION_MODE);
  wifi_station_connect();
  Serial.println("Woke up!");
  delay(10000);
}

void loop()
{
  /* do whatever you want */
  Serial.println("Loop!");
  delay(5000);
}

当我这样说时，请相信我，我已经尝试阅读有关轻度睡眠如何工作的所有内容，我的参考文献包括https://blog.creations.de/?p=149和https://github.com/esp8266/Arduino/issues/1381，但似乎没有任何代码对我有用。我在这里编写的这段代码最接近可以将功耗降低到8mA的地方。根据该文档的说明，我也无法使用此代码进入自动灯光睡眠。

wifi_fpm_close();

这行奇怪地将功耗从8mA增加到〜20mA（文档再次说明）。

问题

我如何进入难以捉摸的1mA强制浅睡眠
无论我对PIN 5做什么，我的系统都不会唤醒。我将如何编写用于唤醒的回调处理程序？或至少让循环在GPIO 5中断上运行。（唤醒中断效果很好，但是“睡眠”时效果不好。）

我在这里做的事完全愚蠢吗？

Answer 1

您的睡眠代码应该在loop（）函数中。您可以这样

#define WAKE_UP_PIN 4

void light_sleep(){
    wifi_fpm_set_sleep_type(LIGHT_SLEEP_T);
    wifi_fpm_open();
    gpio_pin_wakeup_enable(GPIO_ID_PIN(LIGHT_WAKE_PIN), GPIO_PIN_INTR_HILEVEL);
    wifi_fpm_do_sleep(0xFFFFFFF);
}

 void loop(){
   delay(200);
   light_sleep();
   delay(200);
   Serial.println("Wake Up Sid");
 }

我是这样做的，我提到的是您提到的github issue，它对我有用

谢谢

ESP8266中的GPIO唤醒可实现轻度睡眠

1 个答案: