Question

你好，我想创建一个方法来执行以下查询

SELECT * FROM Customer where customer.customerpremium=true;

我很累实现这种方法，但是不起作用。

public interface CustomerRepository extends CrudRepository<Customer, String>{

    Iterable<Customer> findByCustomerPremium(boolean customerpremium);
}

关注我的实体

@Entity
@Table(name = "customer")
public class Customer implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy= GenerationType.AUTO)
    @Column(name = "customerid")
    private Integer customerid;

    @NotEmpty
    @Column(name = "customername")
    private String customername;

    @NotEmpty
    @Column(name = "customeremail")
    private String customeremail;

    @Column(name = "customerpremium")
    private boolean customerpremium;

    /**gets and sets*/
}

Answer 1

您的财产在小写情况下customerpremium

尝试

Iterable<Customer> findByCustomerpremium(boolean customerpremium);

当前这种方法

Iterable<Customer> findByCustomerPremium(boolean customerpremium);

创建这样的查询

SELECT * FROM Customer where customer.customer_premium=:customerpremium;

您还可以通过在application.properties文件中添加以下行来记录您的SQL查询

spring.jpa.show-sql=true

如何使用JPA CrudRepository选择where子句

1 个答案: