Question

考虑这个表

id  -  name  -  age
 1    jonny      12
 2    al         16
 3    lory       22

现在订购年龄我们有Lory，Al，Jonny。

有没有快速的方法来选择jonny在列表中的号码？

考虑到这个顺序SELECT * FROM table ORDER BY age DESC，jonny是第3个。

类似于：SELECT *, * rank(age) as position** FROM table WHERE id = 1

编辑：

我可以统计年龄> gt的记录我的记录：所以查询变为：

SELECT COUNT(id) FROM table WHERE age > (SELECT age FROM table WHERE id = 1) as t1

我接受了答案，但我不喜欢在SQL查询中使用vars。

Answer 1

SELECT
 rownum
FROM
    (
    SELECT @rownum:=@rownum+1 rownum, id,age,name
    FROM (SELECT @rownum:=0) table
    ORDER by age desc
    ) temp
WHERE
    temp.name = 'jonny'

Answer 2

set @name = 'al';
select @name,count(*) + 1 as rank from 
    (select * from `table` where age > 
       (select age from `table` where name=@name) order by age desc)as tab;

mysql计数哪个记录它处于有序模式？

2 个答案: