Question

我有以下问题：我正在发出API请求。带有城市名称“Poznań”（包含某些语言的典型符号），swift不想给我结果，但是当我通过Postman应用程序执行相同的请求时，它会以正确的方式给出结果。如何防止swift从转换那些“奇怪的”字母吗？“ city.name”是我从以前的VC和googlePlaces API传递的城市名称。这是请求的示例以及部分代码： https://samples.openweathermap.org/data/2.5/weather?q=London&appid=b6907d289e10d714a6e88b30761fae22

private let kWeatherAPIURL = "https://api.openweathermap.org/data/2.5/weather?q=%@&appid=%@"

let urlString = String(format: kWeatherAPIURL, city.name, weatherAPIKey)
    guard let url = URL(string: urlString) else {
        print("address doesnt exist!")
        return
    }

Answer 1

为了简洁起见，我被迫在这里展开：

let kWeatherAPIURL = "https://api.openweathermap.org/data/2.5/weather?q=%@&appid=%@"
let weatherAPIKey = "YourWeatherAPIKey"
let cityName = "Poznań"


let cString = cityName.cString(using: .utf8)!
let utf8CityName = cityName.addingPercentEncoding(withAllowedCharacters: .urlHostAllowed)!

let urlString = String(format: kWeatherAPIURL, utf8CityName, weatherAPIKey)
let url = URL(string: urlString)!

//https://api.openweathermap.org/data/2.5/weather?q=Pozna%C5%84&appid=YourWeatherAPIKey

一种安全的方法是使用URL components：

let weatherAPIKey = "YourWeatherAPIKey"
let cityName = "Poznań"


var components = URLComponents()
components.scheme = "https"
components.host = "api.openweathermap.org"
components.path = "/data/2.5/weather"
components.queryItems = [URLQueryItem(name: "q", value: cityName),
                         URLQueryItem(name: "appid", value: weatherAPIKey)
]

print(components.url!)  //https://api.openweathermap.org/data/2.5/weather?q=Pozna%C5%84&appid=YourWeatherAPIKey

Answer 2

使用URLComponents的示例。

准备这样的功能：

func createWeatherAPIURL(cityName: String, apiKey: String) -> URL? {
    let kWeatherAPIURL = "https://api.openweathermap.org/data/2.5/weather"

    var urlCompo = URLComponents(string: kWeatherAPIURL)
    urlCompo?.queryItems = [
        URLQueryItem(name: "q", value: cityName),
        URLQueryItem(name: "appid", value: apiKey)
    ]
    return urlCompo?.url
}

并使用它：

    guard let url = createWeatherAPIURL(cityName: city.name, apiKey: weatherAPIKey) else {
        print("address doesnt exist!")
        return
    }

Swift String忽略/转换波兰口音

2 个答案: