Question

在一个弹出对话框中，我希望将按钮放置在同一行上，但是现在我得到的https://i.stack.imgur.com/sJ30p.png.Following就是给定的样式。

    <PopupDialog
                    ref={popupDialog => {
                      this.popupDialog = popupDialog;
                    }}
                    dialogStyle={{ backgroundColor: "#ddd", height: 200, width:320, border:10,padding:10}}
                    overlayBackgroundColor="#fff"
                    dismissOnTouchOutside={true}
                         >
                 <View style={styles.dialogContentView}>
                 <Text style={{fontSize:18}}>Are you sure you want to submit?</Text>
                 <View style={styles.button_1}>
                 <Button
    title="Yes"
    onPress={() => {
    console.log('clicked')
    }}
    />
    </View>
    <View style={styles.button_1}>
    <Button
    title="No"
    onPress={() => {
    console.log('clicked')
    }}
    />
    </View>
                </View>
                  </PopupDialog>

.....
....

dialogContentView: {
  flex: 1,
    flexDirection: 'column',
    justifyContent: 'space-between'
},
button_1:{

      width: '40%',
      height: 30,

}

Answer 1

在View之后，将Button父元素添加到两个flexDirection: 'row'组件中，其样式为</Text>

<View style={{ flexDirection: 'row' }}>
  <View style={styles.button_1}>
    <Button
      title="Yes"
      onPress={() => {
        console.log('clicked');
      }}
   />
   </View>
   <View style={styles.button_1}>
     <Button
       title="No"
       onPress={() => {
         console.log('clicked');
       }}
     />
   </View>
 </View>

您可以尝试此snack

Answer 2

以全角尝试此操作，没有任何空格或边距 只需复制粘贴

 <View style={{ flexDirection: "row" }}>
     <View style={{ flex: 1 }}>
         <TouchableOpacity style={{ alignSelf: 'stretch',backgroundColor: '#2980B9' }} onPress={() => { onSavePress }}>
              <Text style={{ alignSelf: 'center',
                            color: '#ffffff',
                            fontSize: 16,
                            fontWeight: '600',
                            paddingTop: 10,
                            paddingBottom: 10 }}>Save</Text>
         </TouchableOpacity>
     </View>
     <View style={{borderLeftWidth: 1,borderLeftColor: 'white'}}/>
     <View style={{ flex: 1}}>
         <TouchableOpacity style={{ alignSelf: 'stretch',backgroundColor: '#2980B9'}} onPress={() => { onCancelPress }}>
              <Text style={{ alignSelf: 'center',
                            color: '#ffffff',
                            fontSize: 16,
                            fontWeight: '600',
                            paddingTop: 10,
                            paddingBottom: 10 }}>Cancel</Text>
         </TouchableOpacity>
     </View>
 </View>

Answer 3

为此，我通常创建一个视图，将其flexDirection设置为'row'并将按钮组件放入其中。因此，您的代码将如下所示：

<View style={{ flexDirection: 'row }}>
 <Button title='Button 1'/>
 <Button title='Button 2'/>
</View>

希望对您有帮助。

如何在react native的同一行中放置两个按钮？

3 个答案: