Question

我想更新帖子的隐私

我的控制器

   public function changePostsPrivacy(Request $request){
            $userId = $request->user()->id;
            $postid = $request->get('id');
            //dd($postid);
            $privacy = $request->get('privacy');//dd($privacy);
            $user = User::where(['id' => $userId, 'hide' => 0])->first();
            if($user && $postid && in_array($privacy, [1,0])){
                DB::table('posts')->update(['creator_id' => $userId, 'id' => $postid],[
                    'privacy' => $privacy,
                ]);
            }
        }

路线：

 Route::group(['middleware'=>['auth:api', \App\Http\Middleware\OnlyRegisteredUsers::class]], function(){
        /**
         * Group for registered users only APIs
         */
        Route::post('changePostsPrivacy','UserController@changePostsPrivacy');
    });

迁移

 public function up()
    {
        Schema::create('posts', function (Blueprint $table) {
            $table->increments('id');
            $table->string('title');
            $table->longText('content');
            $table->string('short_description');
            $table->unsignedInteger('media_id')->nullable();
            $table->foreign('media_id')->references('id')->on('medias');
            $table->unsignedInteger('creator_id');
            $table->foreign('creator_id')->references('id')->on('users');
            $table->boolean('hide')->default(0);
            $table->timestamps();
        });
    }

此迁移中添加了新列

 public function up()
        {
            Schema::table('posts', function (Blueprint $table) {
                $table->integer('privacy')->after('creator_id');
            });
        }

当我想在任何帖子中添加隐私时，都会给我一个错误

“消息”：“ SQLSTATE [23000]：违反完整性约束：1451   无法删除或更新父行：外键约束失败   （{webdb。comments，约束comments_post_id_foreign外键   （post_id）参考posts（id））（SQL：更新posts集   creator_id = 17，id = 48）”，

Answer 1

您也可以尝试这个。

$post = Post::where(['creator_id' => $userId, 'id' => $postid])->first();
$post->privacy = $privacy;
$post->save();

Answer 2

您必须在更新隐私信息中使用where条件

DB::table('posts')->where(['creator_id' => $userId, 'id' => $postid])->update(['privacy' => $privacy])

Answer 3

如果您有Post模型，则可以执行以下操作：

Post::where(['creator_id' => $userId, 'id' => $postid])->update(['privacy' => $privacy]);

为防止任何外键错误，应使用validation request检查提供的user_id和post_id exists。

Answer 4

public function changePostsPrivacy(Request $request){
            $userId = $request->user()->id;
            $postid = $request->get('id');
            $privacy = $request->get('privacy');
            $user = User::where(['id' => $userId, 'hide' => 0])->first();
            if($user && $postid && in_array($privacy, [1,0])){
                DB::table('posts')->update([
                    'privacy' => $privacy,
                ]);
            }

创建者ID和ID不需要更新。

更新laravel 5.4中的列值

4 个答案: